java.io.IOException：无法运行程序"WMIC"：创建进程错误=2，系统找不到指定的文件

Question

我想使用java代码获取Windows序列号，但通过异常。我的 java 代码在某些版本的 Windows (7,8( 上运行，不适用于 Windows 10 专业版，并且为相同的代码抛出了异常(未在 Windows vista 上验证(。

public String getWindowKey() {
    String keydata = "";
    try {
        Process process = Runtime.getRuntime().exec(new String[]{"wmic", "diskdrive", "get", "serialnumber"});
        process.getOutputStream().close();
        BufferedReader input
                = new BufferedReader(new InputStreamReader(process.getInputStream()));
        String line;
        String result = "";
        while ((line = input.readLine()) != null) {
            line = line.trim();
            if (line.equalsIgnoreCase("SerialNumber")) {
                continue;
            }
            result += line;
        }
        input.close();
        // String[][] Key = {{"WindowKey", result}};
        keydata = result;
    } catch (Exception ex) {
         LErrorDataLog.info("Exception :" + ex.getMessage());
    }
    return keydata;
}

Answer 1

我遇到了同样的问题。在启动进程之前，我设法通过显式指定进程必须在其中运行的目录来解决此问题：

List<String> cmd = new ArrayList<String>() {{
  add("WMIC.exe"); add("diskdrive"); add("get"); add("serialNumber");
}};
ProcessBuilder pb = new ProcessBuilder().directory(getExecDir());
Process p = pb.command(cmd).start();
// Other code here

getExecDir()方法如下所示：

/**
 * Get the execution directory for WMIC
 * @return File object pointing to the execution directory
 * @throws IOException Execution directory doesn't exist
   */
private static File getExecDir() throws IOException {
  String root = System.getenv("SystemRoot");
  File dir = new File(root, "System32" + File.separatorChar + "wbem");
  if (!dir.exists() || !dir.isDirectory()) {
    throw new IOException('"' + dir.getAbsolutePath() + "" does not exist or is not a directory!");
  }
  return dir;
}