HowTo 将 StackPanel 中所有切换按钮的 IsChecked 属性设置为 false

Question

如何在 StackPanel 中列出所有现有的 ToggleButton 并将其IsChecked属性设置为在代码隐藏中false？

我从：

List<ToggleButton> togglebuttons = togglebtnListSp.Children.OfType<ToggleButton>().ToList();
        foreach(var item in togglebuttons)
        {
          item.IsChecked = false;  
        }

但现在我卡住了，不知道如何确认。

这是我的 XAML：

<!-- Private Customer Rights -->
<StackPanel x:Name="togglebtnListSp">
            <GroupBox x:Name="customerRightsGroupBox" Header="Customer Rights" Margin="10,10,10.2,0" VerticalAlignment="Top" Height="108">
                <Grid>
                    <Grid.ColumnDefinitions>
                        <ColumnDefinition />
                        <ColumnDefinition />
                    </Grid.ColumnDefinitions>
                    <StackPanel Margin="0,0,5,0">
                        <DockPanel LastChildFill="False">
                            <Label Content="Can Add:" DockPanel.Dock="Left" />
                            <ToggleButton x:Name="can_add_customer" DockPanel.Dock="Right"></ToggleButton>
                        </DockPanel>
                        <DockPanel LastChildFill="False">
                            <Label Content="Can Create Assignment:" DockPanel.Dock="Left" />
                            <ToggleButton x:Name="can_add_assignment_customer" DockPanel.Dock="Right"></ToggleButton>
                        </DockPanel>
                    </StackPanel>
                    <StackPanel Grid.Column="1" Margin="5,0,0,0">
                        <DockPanel LastChildFill="False">
                            <Label Content="Can Delete:" DockPanel.Dock="Left" />
                            <ToggleButton x:Name="can_delete_customer" DockPanel.Dock="Right"></ToggleButton>
                        </DockPanel>
                        <DockPanel LastChildFill="False">
                            <Label Content="Can Edit:" DockPanel.Dock="Left" />
                            <ToggleButton x:Name="can_edit_customer" DockPanel.Dock="Right"></ToggleButton>
                        </DockPanel>
                    </StackPanel>
                </Grid>
            </GroupBox>
            <!-- Firm Customer Rights -->
            <GroupBox x:Name="firmCustomerRightsGroupBox" Header="Firmcustomer rights"  Margin="10,10,10,0" VerticalAlignment="Top" Height="108">
                <Grid>
                    <Grid.ColumnDefinitions>
                        <ColumnDefinition />
                        <ColumnDefinition />
                    </Grid.ColumnDefinitions>
                    <StackPanel Margin="0,0,5,0">
                        <DockPanel LastChildFill="False">
                            <Label Content="Can Add:" DockPanel.Dock="Left" />
                            <ToggleButton x:Name="can_add_firmcustomer" DockPanel.Dock="Right"></ToggleButton>
                        </DockPanel>
                        <DockPanel LastChildFill="False">
                            <Label Content="Can create Assignment for firmcustomer" DockPanel.Dock="Left" FontSize="12" />
                            <ToggleButton x:Name="can_add_assignment_firmcustomer" DockPanel.Dock="Right"></ToggleButton>
                        </DockPanel>
                    </StackPanel>
                    <StackPanel Grid.Column="1" Margin="5,0,0,0">
                        <DockPanel LastChildFill="False">
                            <Label Content="Can Delete:" DockPanel.Dock="Left" />
                            <ToggleButton x:Name="can_delete_firmcustomer" DockPanel.Dock="Right"></ToggleButton>
                        </DockPanel>
                        <DockPanel LastChildFill="False">
                            <Label Content="Can edit:" DockPanel.Dock="Left" />
                            <ToggleButton x:Name="can_edit_firmcustomer" DockPanel.Dock="Right"></ToggleButton>
                        </DockPanel>
                    </StackPanel>
                </Grid>
            </GroupBox>
         </StackPanel>

我从数据库中读取假或真。但是，如果我单击"添加"，我希望所有切换按钮都IsChecked="false"

Answer 1

而不是将其添加到列表中，而只是创建一个 linq 命令哪

为您创建列表并为您迭代

YourStackPanel.Children
              .OfType<ToggleButton>().ToList()
                                     .ForEach(toggleButton => toggleButton.IsChecked = false);

Answer 2

试试这个。

for (int i = 0; i < togglebtnListSp.Children.Count; i++)
     if (_panel.Children[i] is ToggleButton)
              ((ToggleButton)_panel.Children[i]).IsChecked = false;

这里发生的事情是代码检查每个孩子，看看它是否是一个切换按钮。如果是这样，请将集合中的 UIElement 对象强制转换为切换按钮，并将IsChecked设置为 false。

Answer 3

在代码隐藏中，您可以使用按类型查找所有元素的方法

public static IEnumerable<T> SeachUiElementsByTypo<T>(DependencyObject depObj) where T : DependencyObject
    {
        if (depObj != null)
        {
            for (int i = 0; i < VisualTreeHelper.GetChildrenCount(depObj); i++)
            {
                DependencyObject child = VisualTreeHelper.GetChild(depObj, i);
                if (child != null && child is T)
                {
                    yield return (T)child;
                }
                foreach (T childOfChild in SeachUiElementsByTypo<T>(child))
                {
                    yield return childOfChild;
                }
            }
        }
    }

像这样使用：

var toggleButtons= UiServices.SeachUiElementsByTypo<ToggleButton>(YourWindow);
foreach (var tb in toggleButtons)
    ((ToggleButton)tb).IsChecked = false