import pandas as pd
df = pd.DataFrame(['Time':['16:47:55.510','16:47:55.511','16:47:55.410']})
df
output:
Time
0 16:47:55.510
1 16:47:55.511
2 16:47:55.410
如何使用 Python 将此时间值转换为浮点值?
如果时间是h:m:s.ms格式,你可以做这样的事情:
hours, minutes, seconds = df.Time[0].split(':')
total_seconds = int(hours) * 3600 + int(minutes) * 60 + float(seconds)