使用 Spotipy 从 Python 中的打印中获取特定行

Question

我正在用Python和Spotipy编写一些代码，我对编码相对较新。我有一些代码可以获取有关Spotify播放列表的所有信息并为我打印出来：

from spotipy.oauth2 import SpotifyClientCredentials
import spotipy
import json

client_credentials_manager = SpotifyClientCredentials()
sp = spotipy.Spotify(client_credentials_manager=client_credentials_manager)
playlist_id = 'spotify:playlist:76CVeJDw2b90up5PgkZXyU'
results = sp.playlist(playlist_id)
#print(json.dumps(results, indent=4))
print((json.dumps(results, indent=4)))

它运行良好，并为我提供了所有信息。我的问题是我只需要打印中的细节：

"collaborative": false,
"description": "",
"external_urls": {
"spotify": "https://open.spotify.com/playlist/76CVeJDw2b90up5PgkZXyU"
},
"followers": {
"href": null,
"total": 0
},
"href": "https://api.spotify.com/v1/playlists/76CVeJDw2b90up5PgkZXyU?additional_types=track",
"id": "76CVeJDw2b90up5PgkZXyU",
"images": [
{
"height": 640,
"url": "https://i.scdn.co/image/ab67616d0000b2734a052b99c042dc15f933145b",
"width": 640
}
],
"name": "TEST",
"owner": {
"display_name": "Name",
"external_urls": {
"spotify": "https://open.spotify.com/user/myname"
},
"href": "https://api.spotify.com/v1/users/myname",
"id": "Myname",
"type": "user",
"uri": "spotify:user:kovizsombor"
},
"primary_color": null,
"public": true,
"snapshot_id": "MixmMGE0MDgxNDQ1ZGVlNmE4MThiMmQwODMwYWU0OTI3YzkyOGJhOWIz",
"tracks": {
"href": "https://api.spotify.com/v1/playlists/76CVeJDw2b90up5PgkZXyU/tracks?offset=0&limit=100&additional_types=track",
"items": [
{
"added_at": "2020-05-17T10:00:11Z",
"added_by": {
"external_urls": {
"spotify": "https://open.spotify.com/user/kovizsombor"
},
"href": "https://api.spotify.com/v1/users/kovizsombor",
"id": "kovizsombor",
"type": "user",
"uri": "spotify:user:kovizsombor"
},
"is_local": false,
"primary_color": null,
"track": {
"album": {
"album_type": "album",
"artists": [
{
"external_urls": {
"spotify": "https://open.spotify.com/artist/0PFtn5NtBbbUNbU9EAmIWF"
},
"href": "https://api.spotify.com/v1/artists/0PFtn5NtBbbUNbU9EAmIWF",
"id": "0PFtn5NtBbbUNbU9EAmIWF",
"name": "TOTO",
"type": "artist",
"uri": "spotify:artist:0PFtn5NtBbbUNbU9EAmIWF"
}
],
],
"external_urls": {
"spotify": "https://open.spotify.com/album/62U7xIHcID94o20Of5ea4D"
},
"href": "https://api.spotify.com/v1/albums/62U7xIHcID94o20Of5ea4D",
"id": "62U7xIHcID94o20Of5ea4D",
"images": [
{
"height": 640,
"url": "https://i.scdn.co/image/ab67616d0000b2734a052b99c042dc15f933145b",
"width": 640
},
{
"height": 300,
"url": "https://i.scdn.co/image/ab67616d00001e024a052b99c042dc15f933145b",
"width": 300
},
{
"height": 64,
"url": "https://i.scdn.co/image/ab67616d000048514a052b99c042dc15f933145b",
"width": 64
}
],
"name": "Toto IV",
"release_date": "1982-04-08",
"release_date_precision": "day",
"total_tracks": 10,
"type": "album",
"uri": "spotify:album:62U7xIHcID94o20Of5ea4D"
},
"artists": [
{
"external_urls": {
"spotify": "https://open.spotify.com/artist/0PFtn5NtBbbUNbU9EAmIWF"
},
"href": "https://api.spotify.com/v1/artists/0PFtn5NtBbbUNbU9EAmIWF",
"id": "0PFtn5NtBbbUNbU9EAmIWF",
"name": "TOTO",
"type": "artist",
"uri": "spotify:artist:0PFtn5NtBbbUNbU9EAmIWF"
}
],
"available_markets": [
],
"disc_number": 1,
"duration_ms": 295893,
"episode": false,
"explicit": false,
"external_ids": {
"isrc": "USSM19801941"
},
"external_urls": {
"spotify": "https://open.spotify.com/track/2374M0fQpWi3dLnB54qaLX"
},
"href": "https://api.spotify.com/v1/tracks/2374M0fQpWi3dLnB54qaLX",
"id": "2374M0fQpWi3dLnB54qaLX",
"is_local": false,
"name": "Africa",
"popularity": 83,
"preview_url": "https://p.scdn.co/mp3-preview/dd78dafe31bb98f230372c038a126b8808f9349b?cid=d568e7073a38465bba48268ea9f10153",
"track": true,
"track_number": 10,
"type": "track",
"uri": "spotify:track:2374M0fQpWi3dLnB54qaLX"
},
"video_thumbnail": {
"url": null
}
}
],
"limit": 100,
"next": null,
"offset": 0,
"previous": null,
"total": 1
},
"type": "playlist",
"uri": "spotify:playlist:76CVeJDw2b90up5PgkZXyU"
}

从这个长打印中，我需要以某种方式提取艺术家和歌曲标题，最好将其变成一个变量。也不确定如果播放列表中有多首歌曲，这将如何工作。

如果我只能打印出艺术家和歌曲的标题而不打印出所有信息，这也是一种解决方案。

Answer 1

根据您发布的示例，您似乎只有 1 首由艺术家"TOTO"命名为"非洲"的歌曲。复制曲目以包含两首歌曲，我添加了另一首带有两位艺术家的曲目以测试数组。

如果将该 json 加载到名为results的变量中，那么(如@xcmkz所说(您有一个 python 字典，可以相应地进行处理。

尝试使用以下方法横向浏览字典，将艺术家和歌曲附加到列表中：

song_dict = {}
for track in results['tracks']['items']:
song_name = track["track"]["name"]
a2 = []
for t1 in track['track']['artists']:
a2.append(t1['name'])
song_dict.update({song_name: a2})
print(f'Dictionary of Songs and Artists:')
for k, v in song_dict.items():
print(f'Song --> {k}, by --> {", ".join(v)}')

结果：

Dictionary of Songs and Artists:
Song --> Africa, by --> TOTO
Song --> Just Another Silly Song, by --> Artist 2, Artist 3

Answer 2

sp.playlist返回字典，因此您可以通过其键简单地访问其值。例如：

>>> results['name']
'TEST'

JSON 是一种数据序列化格式，即将对象表示为纯文本并从文本中解析回来的标准化方式。 因此，json.dumps将字典对象转换为文本字符串。例如，如果您想将结果保存到文件并在以后重新加载，这将非常有用。您不需要它来访问results中的内容。

(不过这是一个播放列表 - 您需要获取每首歌曲/曲目的信息才能获得其艺术家和名称。