PHP curl 文件传输

Question

我们正在使用 GLPI API，我们需要创建一个与文档链接的票证。

我唯一无法翻译的卷曲部分是文档的上传。

使用卷曲(工作(：

curl -i -X POST "http://glpitest/glpi/apirest.php/Document" -H "Content-Type: multipart/form-data" -H "Session-Token:sessiontoken"-H "App-Token:apptoken" -F "uploadManifest={"input": {"name": "Uploaded document", "_filename" : "test.txt"}};type=application/json" -F "filename[0]=@test.txt" "http://glpitest/glpi/apirest.php/Document"

但是我无法翻译这是在 PHP CURL 中，我尝试了这样的事情：

$headers = array(
'Authorization: Basic ' . $_SESSION['encodelogin'],
'App-Token:' . $_SESSION['app_token'], // <---
'Session-Token:' . $_SESSION['session_token'],
'Http_Accept: application/json',
);
curl_setopt($ch, CURLOPT_HTTPHEADER, $headers);
curl_exec($ch);
echo $url = $_SESSION['api_url'] . "/Document";
$cfile = new CURLFile('testpj.txt', 'text/plain', 'test_name');
//$manifest = 'uploadManifest={"input": {"name": "test", "_filename" : "testpj.txt"}};type=application/json filename[0]=@'+$cfile;
$post = ["{"input": {"name": "test", "_filename" : "testpj.txt"}};type=application/json}", @"C:\xampphtdocsglpi"];
print_r($post);
curl_setopt($ch, CURLOPT_URL, $url);
curl_setopt($ch, CURLOPT_POST, 1);
curl_setopt($ch, CURLOPT_POSTFIELDS, $post);
curl_setopt($ch, CURLOPT_RETURNTRANSFER, 1);
$result = curl_exec($ch);

API 中的示例：

$ curl -X POST 
-H 'Content-Type: multipart/form-data' 
-H "Session-Token: 83af7e620c83a50a18d3eac2f6ed05a3ca0bea62" 
-H "App-Token: f7g3csp8mgatg5ebc5elnazakw20i9fyev1qopya7" 
-F 'uploadManifest={"input": {"name": "Uploaded document", "_filename" : ["file.txt"]}};type=application/json' 
-F 'filename[0]=@file.txt' 
'http://path/to/glpi/apirest.php/Document/'
< 201 OK
< Location: http://path/to/glpi/api/Document/1
< {"id": 1, "message": "Document move succeeded.", "upload_result": {...}}

更新：我尝试@hanshenrik但是我有一个错误。

["ERROR_JSON_PAYLOAD_INVALID"，"JSON 有效负载似乎无效"]

在 API 中.class.php ：

if (strpos($content_type, "application/json") !== false) {
if ($body_params = json_decode($body)) {
foreach ($body_params as $param_name => $param_value) {
$parameters[$param_name] = $param_value;
}
} else if (strlen($body) > 0) {
$this->returnError("JSON payload seems not valid", 400, "ERROR_JSON_PAYLOAD_INVALID",
false);
}
$this->format = "json";
} else if (strpos($content_type, "multipart/form-data") !== false) {
if (count($_FILES) <= 0) {

// likely uploaded files is too big so $_REQUEST will be empty also.
// see http://us.php.net/manual/en/ini.core.php#ini.post-max-size
$this->returnError("The file seems too big!".print_r($_FILES), 400,
"ERROR_UPLOAD_FILE_TOO_BIG_POST_MAX_SIZE", false);
}
// with this content_type, php://input is empty... (see http://php.net/manual/en/wrappers.php.php)
if (!$uploadManifest = json_decode(stripcslashes($_REQUEST['uploadManifest']))) {
//print_r($_FILES);
$this->returnError("JSON payload seems not valid", 400, "ERROR_JSON_PAYLOAD_INVALID",
false);
}

我在 $_REQUEST 中没有上传清单，如果我输入文件名[0]文件，我会出现 curl 错误 26(无法读取文件(。

谢谢

Answer 1

翻译

-F "uploadManifest={"input": {"name": "Uploaded document", "_filename" : "test.txt"}};type=application/json"

这很棘手，因为 PHP 并没有真正原生支持将内容类型标头(或任何标头(添加到多部分请求的成员，唯一的*例外*(我知道(是 CURLFile 的"内容类型"和 Content-Disposition 的"文件名"标头...... 考虑到这一点，您可以通过将数据放在文件中并在该虚拟文件周围创建一个 CURLFile(( 来解决此问题，但它是......棘手且看起来很愚蠢(因为 PHP 的 curl api 包装器缺乏适当的支持(

使用 CURLFile 解决方法，它看起来像这样：

<?php
declare(strict_types = 1);
$ch = curl_init();
$stupid_workaround_file1h = tmpfile();
$stupid_workaround_file1f = stream_get_meta_data($stupid_workaround_file1h)['uri'];
fwrite($stupid_workaround_file1h, json_encode(array(
'input' => array(
'name' => 'Uploaded document',
'_filename' => 'test.txt'
)
)));
curl_setopt_array($ch, array(
CURLOPT_URL => "http://glpitest/glpi/apirest.php/Document",
CURLOPT_POST => 1,
CURLOPT_HEADER => 1,
CURLOPT_HTTPHEADER => array(
"Session-Token:sessiontoken",
"App-Token:apptoken"
),
CURLOPT_POSTFIELDS => array(
'uploadManifest' => new CURLFile($stupid_workaround_file1f, 'application/json', ' '), // https://bugs.php.net/bug.php?id=79004
'filename[0]' => new CURLFile('test.txt', 'text/plain')
)
));
curl_exec($ch);
curl_close($ch);
fclose($stupid_workaround_file1h);

Answer 2

感谢您的帮助。

$document可以是 $_FILES["随便"] 帖子。

适用于 GLPI API .

<?php
declare (strict_types = 1);
session_start();
$document = array('name' => 'document', 'path' => 'C:xampphtdocsglpidocument.pdf', 'type' => 'txt', 'name_ext' => 'document.pdf');
$url = $_SESSION['api_url'] . "/Document";
$uploadManifest = json_encode(array(
'input' => array(
'name' => $document['name'],
'_filename' => $document['name_ext'],
),
));
$ch = curl_init();
curl_setopt($ch, CURLOPT_RETURNTRANSFER, 1);
curl_setopt($ch, CURLOPT_HTTPAUTH, CURLAUTH_ANY);
curl_setopt($ch, CURLINFO_HEADER_OUT, 1);
curl_setopt_array($ch, array(
CURLOPT_URL => $url,
CURLOPT_POST => 1,
CURLOPT_HEADER => 1,
CURLOPT_HTTPHEADER => array(
'Content-Type: multipart/form-data',
'Authorization: Basic ' . $_SESSION['encodelogin'],
'App-Token:' . $_SESSION['app_token'], // <---
'Session-Token:' . $_SESSION['session_token'],
),
CURLOPT_POSTFIELDS => array(
'uploadManifest' => $uploadManifest,
'filename[0]' => new CURLFile($document['path'], $document['type'], $document['name_ext']),
),
));
print_r($_REQUEST);
echo $result = curl_exec($ch);
echo "erreur n° " . curl_errno($ch);
$header_info = curl_getinfo($ch, CURLINFO_HEADER_OUT) . "/";
print_r($header_info);
if ($result === false) {
$result = curl_error($ch);
echo stripslashes($result);
}
curl_close($ch);