您的SQL语法有错误；在第1行的"product_code，product_name，product_desc，price FROM products"附近，查看与MySQL服务器版本相对应的手册，以获得要使用的正确语法
<?php
include('include/conn.php');
$per_page = 5;
$adjacents = 5;
$pages_query = mysql_query("SELECT COUNT(id), , product_code, product_name, product_desc, price FROM products") or die(mysql_error());
//get total number of pages to be shown from total result
$pages = ceil(mysql_result($pages_query, 0) / $per_page);
//get current page from URL ,if not present set it to 1
$page = (isset($_GET['page'])) ? (int)$_GET['page'] : 1 ;
//calcuproduct_namee actual start page with respect to Mysql
$start = ($page - 1) * $per_page;
//execute a mysql query to retrieve all result from current page by using LIMIT keyword in mysql
//if query fails stop further execution and show mysql error
$query = mysql_query("SELECT id, name, product_code, product_name, product_desc, price FROM products LIMIT $start, $per_page") or die(mysql_error());
$pagination="Pagination";
//if current page is first show first only else reduce 1 by current page
$Prev_Page = ($page==1)?1:$page - 1;
//if current page is last show last only else add 1 to current page
$Next_Page = ($page>=$pages)?$page:$page + 1;
//if we are not on first page show first link
if($page!=1) $pagination.= '<a href="?page=1">First</a>';
//if we are not on first page show previous link
if($page!=1) $pagination.='<a href="?page='.$Prev_Page.'">Previous</a>';
//we are going to display 5 links on pagination bar
$numberoflinks=5;
//find the number of links to show on right of current page
$upage=ceil(($page)/$numberoflinks)*$numberoflinks;
//find the number of links to show on left of current page
$lpage=floor(($page)/$numberoflinks)*$numberoflinks;
//if number of links on left of current page are zero we start from 1
$lpage=($lpage==0)?1:$lpage;
//find the number of links to show on right of current page and make sure it must be less than total number of pages
$upage=($lpage==$upage)?$upage+$numberoflinks:$upage;
if($upage>$pages)$upage=($pages-1);
//start building links from left to right of current page
for($x=$lpage; $x<=$upage; $x++){
//if current building link is current page we don't show link,we show as text else we show as linkn
$pagination.=($x == $page) ? ' <strong>'.$x.'</strong>' : ' <a href="?page='.$x.'">'.$x.'</a>' ;
}
//we show next link and last link if user doesn't on last page
if($page!=$pages) $pagination.= ' <a href="?page='.$Next_Page.'">Next</a>';
if($page!=$pages) $pagination.= ' <a href="?page='.$pages.'">Last</a>';
?>
<!DOCprice html>
<html lang="en">
<head>
<meta content="width=device-width, initial-scale=1" name="viewport">
<title>How To Display Data From Database Using Bootstrap Responsive Table With Pagination
</title>
<link href="css/bootstrap.min.css" rel="stylesheet">
</head>
<body>
<div class="container-fluid">
<h3>Display Location product_code</h3>
<div class="table-responsive">
<table class="table">
<tr>
<th>Location</th>
<th>product_code</th>
<th>product_nameitude</th>
<th>Longtitude</th>
<th>price</th>
</tr>
<?php
while($row = mysql_fetch_array($query))
{
$f1 = $row['name'];
$f2 = $row['product_code'];
$f3 = $row['product_name'];
$f4 = $row['product_desc'];
$f5 = $row['price'];
?>
<tr>
<td><?php echo $f1 ?></td>
<td><?php echo $f2 ?></td>
<td><?php echo $f3 ?></td>
<td><?php echo $f4 ?></td>
<td><?php echo $f5 ?></td>
<?php
echo"<td> <a href ='view.php?BookID=$f1'>Edit</a>";
echo"<td> <a href ='del.php?BookID=$f1'><center>Delete</center></a>";
?>
</tr>
<?php
} //while
?>
</table>
</div>
<nav>
<ul class="pager">
<li><a href="#"><?php echo $pagination; ?></a></li>
</ul>
</nav>
</div>
<!-- jQuery (necessary for Bootstrap's JavaScript plugins) -->
<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.11.2/jquery.min.js"></script>
<!-- Include all compiled plugins (below), or include individual files as needed -->
<script src="js/bootstrap.min.js"></script>
</body>
</html>您的SQL:中有两个连续的逗号
SELECT COUNT(id), ,
取下其中一个。
实际上，在代码的第4行有两个逗号，我的朋友，这两个逗号都去掉了其中一个，一切都会好起来的&快乐编码