我正在尝试对表"apst_mailings"运行查询,该表存储了我们发送给订阅者的每份时事通讯的内容。每次我们尝试将电子邮件发送给个人时,我们都会在apst_mailings_accuses中插入一行,报告发送的时间和状态以及新字母的 ID。我想列出新闻通讯并计算每个时事通讯发送和成功发送的总数。
SELECT m.id AS code_mailing,
COUNT(a.adh_code) AS num, COUNT(b.adh_code) AS succes
FROM apst_mailings AS m
LEFT OUTER JOIN apst_mailings_accuses AS a
ON a.id_mailing = m.id
LEFT OUTER JOIN apst_mailings_accuses AS b
ON b.id_mailing = m.id
AND b.etat = 'succes'
GROUP BY m.id
它只是永远挂起服务器。我已经尝试了单独查询中的每个连接,并且没有问题:
// Counts the email sent per mailing
SELECT m.id AS code_mailing,
COUNT(a.adh_code) AS num
FROM apst_mailings AS m
LEFT OUTER JOIN apst_mailings_accuses AS a
ON a.id_mailing = m.id
GROUP BY m.id
SELECT m.id AS code_mailing,
COUNT(b.adh_code) AS succes
FROM apst_mailings AS m
LEFT OUTER JOIN apst_mailings_accuses AS b
ON b.id_mailing = m.id
AND b.etat = 'succes'
GROUP BY m.id
我可以拆分我的查询,但它不起作用的原因真的很困扰我。谁能解释一下?
谢谢!
通过使用单个联接并使用SUM
执行条件计数,您可以以更简单的方式实现所需的内容。
SELECT
m.id AS code_mailing,
COUNT(a.adh_code) AS num,
SUM(a.etat = 'succes') AS succes
FROM apst_mailings AS m
LEFT OUTER JOIN apst_mailings_accuses AS a
ON a.id_mailing = m.id
GROUP BY m.id
但是您的查询不起作用的原因是,您将子查询 a 中的所有行与子查询 b 中的所有匹配行连接在一起,形成了一个巨大的交叉连接。这可能会生成一个巨大的临时结果集,这大概就是查询需要永远终止的原因。即使它确实终止了,你的计数也会完全关闭 - 它们将是两个计数的乘积。
要解决它,请先做GROUP BY
。然后将结果JOIN
到主表。
SELECT
m.id AS code_mailing,
IFNULL(a.num, 0) AS num,
IFNULL(b.succes, 0) AS succes
FROM apst_mailings AS m
LEFT OUTER JOIN (
SELECT id_mailing, COUNT(adh_code) AS num
FROM apst_mailings_accuses
GROUP BY id_mailing
) a
ON a.id_mailing = m.id
LEFT OUTER JOIN (
SELECT id_mailing, COUNT(adh_code) AS succes
FROM apst_mailings_accuses
WHERE etat = 'succes'
GROUP BY id_mailing
) b
ON b.id_mailing = m.id