Gulp-js 任务用于缩小未缩小的文件并与缩小的文件连接

Question

如何编写一个gulp-js任务，该任务仅缩小未缩小的文件并将它们与已经缩小的文件连接起来。

Answer 1

//Minify and transfer non-minified files to a temp folder
gulp.task('scripts1', function() {
  return gulp.src(['js/*.js', '!js/*.min.js'])
    .pipe(fixmyjs({}))
    .pipe(jshint('.jshintrc'))
    .pipe(jshint.reporter('default'))
    .pipe(rename({suffix: '.min'}))
    .pipe(uglify())
    .pipe(gulp.dest('dist/assets/js/new'))
    //.pipe(notify({ message: 'Scripts1 task complete to minify' }));
});
//transfer minified files to the same temp folder
gulp.task('scripts2',['scripts1'], function() {
  return gulp.src(['js/*.min.js','js/rev-slider/*.min.js'])
    .pipe(gulp.dest('dist/assets/js/new'))
    //.pipe(notify({ message: 'Scripts2 task complete to copy minified files' }));
});
//concat all minified files to a new dist folder
gulp.task('scripts3',['scripts2'], function() {
  return gulp.src('dist/assets/js/new/*.min.js')
    .pipe(order([
                'dist/assets/js/new/jquery-1.10.2.min.js',
                'dist/assets/js/new/bootstrap.min.js',
                'dist/assets/js/new/jquery.appear.min.js',
                'dist/assets/js/new/jquery.countTo.min.js',
                'dist/assets/js/new/waypoints.min.js',
                'dist/assets/js/new/jquery.prettyPhoto.min.js',
                'dist/assets/js/new/modernizr-latest.min.js',
                'dist/assets/js/new/SmoothScroll.min.js',
                'dist/assets/js/new/jquery.parallax-1.1.3.min.js',
                'dist/assets/js/new/jquery.easing.1.3.min.js',
                'dist/assets/js/new/jquery.sticky.min.js',
                'dist/assets/js/new/owl.carousel.min.js',
                'dist/assets/js/new/jquery.isotope.min.js',
                'dist/assets/js/new/jquery.themepunch.plugins.min.js',
                'dist/assets/js/new/jquery.themepunch.revolution.min.js',
                'dist/assets/js/new/jquery.mb.YTPlayer.min.js',
                'dist/assets/js/new/jquery.mapmarker.min.js',
                'dist/assets/js/new/scripts.min.js'
            ], { base: './' }))
    .pipe(concat('scripts.min.js'))
    .pipe(gulp.dest('dist/assets/js'))
    .pipe(notify({ message: 'Scripts3 task complete to concat all minified files' }));
});
//delete the temp folder
gulp.task('cleantempjs',['scripts3'], function(cb) {
    del('dist/assets/js/new', cb)
});
//Now run the default task with clean task
gulp.task('clean', function(cb) {
   del(['dist/assets/css', 'dist/assets/js', 'dist/assets/img'], cb)
});
gulp.task('default', ['clean'], function() {
   gulp.start('cleantempjs');
});

Answer 2

gulp-minify有一个ignoreFiles选项，因此您可以传递流中的所有文件，并在应用minify时对其进行区分。