如何将此脚本修复到在文本区域中重复出现的彩色单词



我正在编写一个脚本来查找和着色值,这些值在我的文本区域中重复出现,我用作分隔符:" |",",","〜",i尝试用文本中的单词频率构造数组,然后我只是构建一个单词列表,在文本中重复出现,称为:colorwords,看起来像这样:

var colorWords = Object.keys(filtered)

然后,我试图通过创建一种找到它们的方法并用特定颜色替换字符串的方法来染色:

'<span style="color:'+colors[Math.floor((Math.random(148) * colors.length) + 1)]+'">'+colorWords[i]+'</span>'

我正在使用一个随机生成器来分配颜色,但是我无法颜色重复的单词着色,因为我的脚本正在着色,其中包含我列表的单词的字符的所有匹配称为colorwords,它正在着色所有" x",以及所有匹配的子字符串,我想修复它并改进我的代码,我的完整代码看起来像:

<!DOCTYPE html>
<html><head><meta http-equiv="Content-Type" content="text/html; charset=windows-1252"><script src="./code33_files/lodash.js"></script> 
</head><body>
<p id="demo"></p>
<textarea cols="150" rows="15" id="texto">
"RBD|X|RBD3|C|92173~GJHGWO.NAYE" "SAMBORNSiPOSSSTHRa1"
"RBD|X|RBD|C|92173~GJHGX4.NAYE" "SAMBORNSiPOSSSTHRa"
"RBD|X3|RBD3|C|92173~GJHGX6.NAYE" "SAMBORNSiPOSSSTHRa1"
"RBD|X|RBD|C|92173~GJHGX8.NAYE" "SAMBORNSiPOSSSTHRa2"
"RBD|X|RBD|C|92173~GJHGXA.NAYE" "SAMBORNSiPOSSSTHRa2"
"RBD|X3|RBD|C|92173~GJHGXC.NAYE" "SAMBORNSiPOSSSTHRa"
</textarea>
<div id="out1"></div>
<script>
var text = document.getElementById("texto").value;
var splitWords = text.split(/[["|~]/);
var cleanArray  = _.remove(splitWords, function (word) {return word !== '' && word !== ' ' && word !== 'n'});
var dict = cleanArray.reduce(function(p,c) {
    if (p[c] === undefined) {
        p[c] = 1;
    } else {
        p[c]++;
    }
    return p;
},{});
console.log(dict);
var filtered = Object.keys(dict).reduce(function (filtered, key) {
    if (dict[key] > 1) filtered[key] = dict[key];
    return filtered;
}, {});
var colorWords = Object.keys(filtered)
colors = ["AliceBlue","AntiqueWhite","Aqua","Aquamarine","Azure","Beige","Bisque","Black","BlanchedAlmond","Blue","BlueViolet","Brown","BurlyWood","CadetBlue","Chartreuse","Chocolate","Coral","CornflowerBlue","Cornsilk","Crimson","Cyan","DarkBlue","DarkCyan","DarkGoldenRod","DarkGray","DarkGrey","DarkGreen","DarkKhaki","DarkMagenta","DarkOliveGreen","DarkOrange","DarkOrchid","DarkRed","DarkSalmon","DarkSeaGreen","DarkSlateBlue","DarkSlateGray","DarkSlateGrey","DarkTurquoise","DarkViolet","DeepPink","DeepSkyBlue","DimGray","DimGrey","DodgerBlue","FireBrick","FloralWhite","ForestGreen","Fuchsia","Gainsboro","GhostWhite","Gold","GoldenRod","Gray","Grey","Green","GreenYellow","HoneyDew","HotPink","IndianRed","Indigo","Ivory","Khaki","Lavender","LavenderBlush","LawnGreen","LemonChiffon","LightBlue","LightCoral","LightCyan","LightGoldenRodYellow","LightGray","LightGrey","LightGreen","LightPink","LightSalmon","LightSeaGreen","LightSkyBlue","LightSlateGray","LightSlateGrey","LightSteelBlue","LightYellow","Lime","LimeGreen","Linen","Magenta","Maroon","MediumAquaMarine","MediumBlue","MediumOrchid","MediumPurple","MediumSeaGreen","MediumSlateBlue","MediumSpringGreen","MediumTurquoise","MediumVioletRed","MidnightBlue","MintCream","MistyRose","Moccasin","NavajoWhite","Navy","OldLace","Olive","OliveDrab","Orange","OrangeRed","Orchid","PaleGoldenRod","PaleGreen","PaleTurquoise","PaleVioletRed","PapayaWhip","PeachPuff","Peru","Pink","Plum","PowderBlue","Purple","RebeccaPurple","Red","RosyBrown","RoyalBlue","SaddleBrown","Salmon","SandyBrown","SeaGreen","SeaShell","Sienna","Silver","SkyBlue","SlateBlue","SlateGray","SlateGrey","Snow","SpringGreen","SteelBlue","Tan","Teal","Thistle","Tomato","Turquoise","Violet","Wheat","White","WhiteSmoke","Yellow","YellowGreen"]
for (i = 0; i < colorWords.length; i++) { 
    word=colorWords[i];
    text = text.replace(new RegExp(word, 'g'), '<span style="color:'+colors[Math.floor((Math.random(148) * colors.length) + 1)]+'">'+colorWords[i]+'</span>');
}
document.getElementById("out1").innerHTML = text;
</script>
</body></html>

我要求不要将这个问题视为达成这个问题,我想说的是,我正在搜索解决替换的方法,以下是:

for (i = 0; i < colorWords.length; i++) { 
    word=colorWords[i];
    text = text.replace(new RegExp(word, 'g'), '<span style="color:'+colors[Math.floor((Math.random(148) * colors.length) + 1)]+'">'+colorWords[i]+'</span>');
}

以及改进代码的方法,因为这是我最初使用的方法来解决问题,并且要对字符串进行颜色,我也会在显示textarea coloreated coloreated时之间的分离,我想修复我感谢有关如何实现这一目标的建议。

https://jsfiddle.net/tfhg9ccd/使用REGEXP修改(使用" b"):

new RegExp("\b"+word+"\b", 'g')

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