我有一个字符串，它可能很长，包含各种行和字符。
我想提取所有被SB&EB：
SB1EB
SBa description of various lengthEB
SB123.456.78EB
SB99.99EB
SB99.99EB
SB2EB
SBanother description of various lengthEB
SB123.456.00EB
SB199.99EB
SB199.99EB
3
another description of various length that I don't want to return
123.456.00
599.99
599.99
SB60EB
SBanother description of various length that i want to keepEB
SB500.256.10EB
SB0.99EB
SB0.99EB
another bit of text that i don't want - can span multiple lines
这是我在PHP中使用的模式：
preg_match_all('/SB(d+)EBnSB(w.*)EBnSB(d{3}.d{3}.d{2})EBnSB(d.*)EBnSB(d.*)EBn/', $string, $matches)
因此，这应该有望回归：
[0] -> SB1EB
SBa description of various lengthEB
SB123.456.78EB
SB99.99EB
SB99.99EB
[1] -> SB2EB
SBanother description of various lengthEB
SB123.456.00EB
SB199.99EB
SB199.99EB
[2] -> SB60EB
SBanother description of various length that i want to keepEB
SB500.256.10EB
SB0.99EB
SB0.99EB
但我显然做错了什么，因为它与任何东西都不匹配。有人能帮忙吗？
解决方案：
基于@Sajid回复：
if (preg_match_all('/(?:SB.+?EB(?:[rn]+|$))/', $string, $result)) {
for($i=0;$i<count($result[0]);$i++){
$single_item = $result[0][$i];
$single_item = str_replace("SB","",$single_item);
$single_item = str_replace("EB","",$single_item);
if (preg_match('/(d{3}.d{3}.d{2})/', $single_item)) {
$id = $single_item;
$qty = $result[0][$i-2];
$name = $result[0][$i-1];
$price = $result[0][$i+1];
$total = $result[0][$i+2];
}
}
}
它有点乱，但它有效！：(
感谢
有点破解，但这可以完成任务：
$a = array();
if (preg_match_all('/(?:SB.+?EB(?:[rn]+|$)){5}/', $x, $a)) {
print_r($a);
}
注意了吗？：用于使组不被捕获，结果将在$a[0](例如，$a[0][0]、$a[0][1]、$a[0][2]…(中
基于@Sajid回复：
if (preg_match_all('/(?:SB.+?EB(?:[rn]+|$))/', $string, $result))
{
for ($i=0; $i<count($result[0]); $i++)
{
$single_item = $result[0][$i];
$single_item = str_replace("SB","",$single_item);
$single_item = str_replace("EB","",$single_item);
if (preg_match('/(d{3}.d{3}.d{2})/', $single_item))
{
$id = $single_item;
$qty = $result[0][$i-2];
$name = $result[0][$i-1];
$price = $result[0][$i+1];
$total = $result[0][$i+2];
}
}
}
它有点乱，但它有效！：(
preg_match_all('/SBd+EB.*?(?=(?:SBd+EB)|$)/s', $subject, $result, PREG_PATTERN_ORDER);
for ($i = 0; $i < count($result[0]); $i++) {
# Matched text = $result[0][$i];
}
因此，基本上，我所做的(基于您的输入(只是简单地检查"标头"字符串SB\d+EB作为入口点，并消耗所有内容，直到我找到另一个"标头"或输入的末尾。请注意/s修饰符，以便。匹配换行符。
解释：
# SBd+EB.*?(?=(?:SBd+EB)|$)
#
# Options: dot matches newline
#
# Match the characters “SB” literally «SB»
# Match a single digit 0..9 «d+»
# Between one and unlimited times, as many times as possible, giving back as needed (greedy) «+»
# Match the characters “EB” literally «EB»
# Match any single character «.*?»
# Between zero and unlimited times, as few times as possible, expanding as needed (lazy) «*?»
# Assert that the regex below can be matched, starting at this position (positive lookahead) «(?=(?:SBd+EB)|$)»
# Match either the regular expression below (attempting the next alternative only if this one fails) «(?:SBd+EB)»
# Match the regular expression below «(?:SBd+EB)»
# Match the characters “SB” literally «SB»
# Match a single digit 0..9 «d+»
# Between one and unlimited times, as many times as possible, giving back as needed (greedy) «+»
# Match the characters “EB” literally «EB»
# Or match regular expression number 2 below (the entire group fails if this one fails to match) «$»
# Assert position at the end of the string (or before the line break at the end of the string, if any) «$»