Java小程序访问控制异常(apachehttpclient)

Question

我有以下HttpGet（）函数：

    HttpGet request = new HttpGet(url);
    request.setHeader("User-Agent", userAgent);
    request.setHeader("Accept", "text/html,application/xhtml+xml,application/xml;q=0.9,*/*;q=0.8");
    request.setHeader("Accept-Language", "en-US,en;q=0.5");
    if (!cookies.equals(""))
        request.setHeader("Cookie", this.cookies);
    for (Map.Entry<String, String> header : tempHeaders.entrySet())
    {
        request.setHeader(header.getKey(), header.getValue());
    }
    tempHeaders.clear();
    HttpResponse response = client.execute(request);

这个函数是封装Apache的HttpClient的Browser（）类的一部分。当我在小程序查看器中运行小程序时，一切都很好。然而，当我将小程序嵌入到页面中时，我会得到以下异常：

java.security.AccessControlException: access denied ("java.net.SocketPermission" "127.0.0.1:80" "connect,resolve")
    at java.security.AccessControlContext.checkPermission(Unknown Source)
    at java.security.AccessController.checkPermission(Unknown Source)
    at java.lang.SecurityManager.checkPermission(Unknown Source)
    at java.lang.SecurityManager.checkConnect(Unknown Source)
    at sun.plugin2.applet.SecurityManagerHelper.checkConnectHelper(Unknown Source)
    at sun.plugin2.applet.AWTAppletSecurityManager.checkConnect(Unknown Source)
    at java.net.Socket.connect(Unknown Source)
    at org.apache.http.conn.scheme.PlainSocketFactory.connectSocket(PlainSocketFactory.java:117)
    at org.apache.http.impl.conn.DefaultClientConnectionOperator.openConnection(DefaultClientConnectionOperator.java:178)
    at org.apache.http.impl.conn.ManagedClientConnectionImpl.open(ManagedClientConnectionImpl.java:304)
    at org.apache.http.impl.client.DefaultRequestDirector.tryConnect(DefaultRequestDirector.java:610)
    at org.apache.http.impl.client.DefaultRequestDirector.execute(DefaultRequestDirector.java:445)
    at org.apache.http.impl.client.AbstractHttpClient.doExecute(AbstractHttpClient.java:863)
    at org.apache.http.impl.client.CloseableHttpClient.execute(CloseableHttpClient.java:82)
    at org.apache.http.impl.client.CloseableHttpClient.execute(CloseableHttpClient.java:106)
    **at vidinstant.HttpBrowser.Get(HttpBrowser.java:60)**
    at vidinstant.ServerThread$1.run(ServerThread.java:201)
    at vidinstant.ServerThread$1.run(ServerThread.java:197)
    at java.security.AccessController.doPrivileged(Native Method)
    at vidinstant.ServerThread.GetLink(ServerThread.java:196)
    at vidinstant.ServerThread.run(ServerThread.java:95)

您可以看到异常的"源"在Browser类中的第60行，更准确地说，是上面代码摘录中的这一行：

  HttpResponse response = client.execute(request);

我已经对applet.jar进行了自签名，清单文件中有一行"权限：所有权限"。

为什么我会得到这个异常，为什么访问被拒绝？在浏览器中运行小程序的用户单击"允许"one_answers"不阻止"，但它仍然不起作用。Apache的library.jar也必须签名吗？他们需要在清单中有"所有许可"吗？如何在用户不必篡改Java策略文件的情况下获得运行此类函数的权限

Answer 1

Apache的library.jar也必须签名吗？

是的。不允许"90%"安全。部署的代码被认为是安全的，。。或者不安全。