我想从联系人电子邮件中检索联系人姓名,所以我所做的如下https://stackoverflow.com/a/18064869/5738881.
public static String readContacts(Context context, String email) {
ContentResolver cr = context.getContentResolver();
Uri uri = Uri.withAppendedPath(ContactsContract.PhoneLookup.CONTENT_FILTER_URI, Uri.encode(email));
Cursor cursor = cr.query(uri, new String[]{ContactsContract.PhoneLookup.DISPLAY_NAME}, null, null, null);
if (cursor == null) {
return null;
}
String contactName = null;
if (cursor.moveToFirst()) {
contactName = cursor.getString(cursor.getColumnIndex(ContactsContract.PhoneLookup.DISPLAY_NAME));
}
if (!cursor.isClosed()) {
cursor.close();
}
Log.e("....contact name....", email + "n" + contactName);
return contactName;
}
然后在onCreate()中,我编码为,
sName = readContacts(getApplicationContext(), sEmail);
etName.setText(sName);
但我得到的是null值。因此,根据联系人的电子邮件地址,获取联系人姓名的方法是什么?
第1版:
我已经在清单中提到了许可,
<uses-permission android:name="android.permission.READ_CONTACTS"/>
第2版:
根据ROHIT SHARMA的回答,我将代码更改如下。
public static String readContacts(Context context, String email) {
ContentResolver cr = context.getContentResolver();
Uri uri = Uri.withAppendedPath(ContactsContract.PhoneLookup.CONTENT_FILTER_URI, Uri.encode(email));
Cursor cursor = cr.query(uri, new String[]{ContactsContract.PhoneLookup.DISPLAY_NAME}, null, null, null);
if (cursor == null) {
return null;
}
String contactName = null;
if (cursor.getCount() > 0) {
cursor.moveToFirst();
} else {
return null;
}
if (cursor.moveToFirst()) {
contactName = cursor.getString(cursor.getColumnIndex(ContactsContract.PhoneLookup.DISPLAY_NAME));
}
if (!cursor.isClosed()) {
cursor.close();
}
Log.e("....contact name....", email + "n" + contactName);
return contactName;
}
但这对我没有帮助。
第3版:
public static String readContacts(Context context, String email) {
ContentResolver cr = context.getContentResolver();
Uri uri = Uri.withAppendedPath(ContactsContract.PhoneLookup.CONTENT_FILTER_URI, Uri.encode(email));
Cursor cursor = cr.query(uri, new String[]{ContactsContract.PhoneLookup.DISPLAY_NAME}, null, null, null);
String contactName = null;
if(cursor!=null && cursor.getCount()>0 )
{
cursor.moveToFirst();
contactName = cursor.getString(cursor.getColumnIndex(ContactsContract.PhoneLookup.DISPLAY_NAME));
}else{
return null;
}
if (!cursor.isClosed()) {
cursor.close();
}
Log.e("....contact name....", email + "n" + contactName);
return contactName;
}
这对我也没有帮助。
第4版:
我试过
public String readContacts(Context context, String email) {
String name = null;
// define the columns I want the query to return
String[] projection = new String[]{
ContactsContract.PhoneLookup.DISPLAY_NAME,
ContactsContract.PhoneLookup._ID};
// encode the email and build the filter URI
Uri contactUri = Uri.withAppendedPath(ContactsContract.PhoneLookup.CONTENT_FILTER_URI, Uri.encode(email));
// query time
Cursor cursor = context.getContentResolver().query(contactUri, projection, null, null, null);
if (cursor != null) {
if (cursor.moveToFirst()) {
name = cursor.getString(cursor.getColumnIndex(ContactsContract.PhoneLookup.DISPLAY_NAME));
Log.e("....email.....", "Started uploadcontactphoto: Contact Found @ " + email);
Log.e("....name....", "Started uploadcontactphoto: Contact name = " + name);
} else {
Log.e("....email exception....", "Contact Not Found @ " + email);
}
cursor.close();
}
return name;
}
来自https://stackoverflow.com/a/15007980/5738881但也无济于事。
有没有其他出路?
第5版:
public String readContacts() {
ContentResolver cr = getContentResolver();
@SuppressLint("Recycle")
Cursor cur = cr.query(ContactsContract.Contacts.CONTENT_URI,
null, null, null, null);
String id, name = null, email = null;
if (cur != null && cur.getCount() > 0) {
while (cur.moveToNext()) {
id = cur.getString(cur.getColumnIndex(ContactsContract.Contacts._ID));
name = cur.getString(cur.getColumnIndex(ContactsContract.Contacts.DISPLAY_NAME));
if (Integer.parseInt(cur.getString(cur.getColumnIndex(ContactsContract.Contacts.HAS_PHONE_NUMBER))) > 0) {
System.out.println("name : " + name + ", ID : " + id);
// get the phone number
Cursor pCur = cr.query(ContactsContract.CommonDataKinds.Phone.CONTENT_URI, null,
ContactsContract.CommonDataKinds.Phone.CONTACT_ID + " = ?",
new String[]{id}, null);
if (pCur != null) {
while (pCur.moveToNext()) {
String phone = pCur.getString(
pCur.getColumnIndex(ContactsContract.CommonDataKinds.Phone.NUMBER));
System.out.println("phone" + phone);
}
}
if (pCur != null) {
pCur.close();
}
// get email and type
Cursor emailCur = cr.query(
ContactsContract.CommonDataKinds.Email.CONTENT_URI,
null,
ContactsContract.CommonDataKinds.Email.CONTACT_ID + " = ?",
new String[]{id}, null);
if (emailCur != null) {
while (emailCur.moveToNext()) {
// This would allow you get several email addresses
// if the email addresses were stored in an array
email = emailCur.getString(
emailCur.getColumnIndex(ContactsContract.CommonDataKinds.Email.DATA));
String emailType = emailCur.getString(
emailCur.getColumnIndex(ContactsContract.CommonDataKinds.Email.TYPE));
System.out.println("Email " + email + " Email Type : " + emailType);
}
if (email == sEmail) {
sName = name;
}
}
if (emailCur != null) {
emailCur.close();
}
}
}
}
return name;
}
我从中尝试了以上代码实例http://www.coderzheaven.com/2011/06/13/get-all-details-from-contacts-in-android/我得到了名字,但它和电子邮件id所有者的名字不同。
那么,告诉我哪里出了问题。。
从上面的代码片段来看,我也尝试过
if (email == sEmail) {
sName = name;
}
System.out.println("Email " + email + " Email Type : " + emailType);
}
}
if (emailCur != null) {
emailCur.close();
}
而不是
System.out.println("Email " + email + " Email Type : " + emailType);
}
if (email == sEmail) {
sName = name;
}
}
if (emailCur != null) {
emailCur.close();
}
但也无济于事。
您应该更换
Uri uri = Uri.withAppendedPath(ContactsContract.PhoneLookup.CONTENT_FILTER_URI, Uri.encode(email));
Cursor cursor = cr.query(uri, new String[]{ContactsContract.PhoneLookup.DISPLAY_NAME}, null, null, null);
带有
Uri uri = Uri.withAppendedPath(ContactsContract.CommonDataKinds.Email.CONTENT_FILTER_URI, Uri.encode(email));
Cursor cursor = cr.query(uri, new String[]{ContactsContract.CommonDataKinds.Email.CONTACT_ID,
ContactsContract.Data.DISPLAY_NAME}, null, null, null);
然后测试它。
使用getCount之前,请始终检查它。
if(cursor!=null && cursor.getCount()>0 )
{
cursor.moveToFirst();
}else{
return null;
}
还要检查您是否已声明允许读取清单中的联系人:
<uses-permission android:name="android.permission.READ_CONTACTS" />
您还需要一些其他相关权限,请查看文档中的内容以了解哪些权限。
我建议尝试这种方式,并使用断点调试代码问题出在哪里。
public static String readContacts(Context context, String email) {
ContentResolver cr = context.getContentResolver();
Uri uri = Uri.withAppendedPath(ContactsContract.PhoneLookup.CONTENT_FILTER_URI, Uri.encode(email));
Cursor cursor = cr.query(uri, new String[]{ContactsContract.PhoneLookup.DISPLAY_NAME}, null, null, null);
String contactName = null;
if(cursor!=null && cursor.getCount()>0 )
{
cursor.moveToFirst();
contactName = cursor.getString(cursor.getColumnIndex(ContactsContract.PhoneLookup.DISPLAY_NAME));
}else{
return null;
}
if (!cursor.isClosed()) {
cursor.close();
}
Log.e("....contact name....", email + "n" + contactName);
return contactName;
}