如何将对象添加到对象哈希映射中的排序集



我正在尝试将乘客对象添加到排序集中。此排序集位于巡航对象中。所有巡航对象都在哈希映射中。我对收藏有点陌生,所以我遇到了麻烦。这是我尝试做我正在做的事情。

HashMap<String, Cruise> cruiseMap = new HashMap<String, Cruise>();
SortedSet<Passenger> passengerSet = new TreeSet<Passenger>();
Queue<Passenger> waitingList = new LinkedList<Passenger>();
Cruise cruise = new Cruise("1", passengerSet, waitingList, false);
cruiseMap.put("1", cruise);
Passenger passenger = new Passenger("Smith", "J");
cruiseMap.get("1").getPassengerSet().add(passenger);
乘客的参数是字符串,这些

字符串是姓氏,然后是他们的第一个首字母。邮轮的参数是日期的字符串,排序设置乘客,等待列表队列和布尔变量来确定船是否已出发。当我运行这段代码时,我不断收到大量错误。提前感谢您的帮助。

这是我收到的错误。

Exception in thread "main" java.lang.ClassCastException: edu.ilstu.Passenger cannot be cast to java.lang.Comparable
at java.util.TreeMap.compare(Unknown Source)
at java.util.TreeMap.put(Unknown Source)
at java.util.TreeSet.add(Unknown Source)
at edu.ilstu.Driver.main(Driver.java:48)

乘客舱位

public class Passenger {
    private String lastName = "";
    private String firstName = "";
    public Passenger()
    {
        lastName = "no last name yet";
        firstName = "no first name yet";
    }
    public Passenger(String lastName, String firstName)
    {
        this.lastName = lastName;
        this.firstName = firstName;
    }
    /**
     * @return the lastName
     */
    public String getLastName()
    {
        return lastName;
    }
    /**
     * @param lastName the lastName to set
     */
    public void setLastName(String lastName)
    {
    this.lastName = lastName;
    }
    /**
     * @return the firstName
     */
    public String getFirstName()
    {
        return firstName;
    }
    /**
     * @param firstName the firstName to set
     */
    public void setFirstName(String firstName)
    {
        this.firstName = firstName;
    }
    /* (non-Javadoc)
     * @see java.lang.Object#toString()
     */
    @Override
    public String toString()
    {
        return lastName + " " + firstName;
    }
}

邮轮舱

public class Cruise
    {
    private String day = "";
    private  SortedSet<Passenger> passengerSet = new TreeSet<Passenger>();
    private Queue<Passenger> waitingList = new LinkedList<Passenger>();
    private boolean hasDeparted = false;
    public Cruise()
    {
        day = "no day yet";
        passengerSet = null;
        waitingList = null;
        hasDeparted = false;
    }
    public Cruise(String day, SortedSet<Passenger> passengerSet,     Queue<Passenger> waitingList, boolean hasDeparted)
    {
        this.day = day;
        this.passengerSet = passengerSet;
        this.waitingList = waitingList;
        this.hasDeparted = hasDeparted;
    }
    /**
     * @return the day
     */
    public String getDay()
    {
        return day;
    }
    /**
     * @param day the day to set
     */
    public void setDay(String day)
    {
        this.day = day;
    }
    /**
     * @return the passengerSet
     */
    public SortedSet<Passenger> getPassengerSet()
    {
        return passengerSet;
    }
    /**
     * @param passengerSet the passengerSet to set
     */
    public void setPassengerSet(SortedSet<Passenger> passengerSet)
    {
        this.passengerSet = passengerSet;
    }
    /**
     * @return the waitingList
     */
    public Queue<Passenger> getWaitingList()
    {
        return waitingList;
    }
    /**
     * @param waitingList the waitingList to set
     */
    public void setWaitingList(Queue<Passenger> waitingList)
    {
        this.waitingList = waitingList;
    }
    /**
     * @return the hasDeparted
     */
    public boolean isHasDeparted()
    {
        return hasDeparted;
    }
    /**
     * @param hasDeparted the hasDeparted to set
     */
    public void setHasDeparted(boolean hasDeparted)
    {
        this.hasDeparted = hasDeparted;
    }
}

发生这种情况是因为您的passengerSet TreeSet(SortedSet(,这意味着它将在每次添加后自行排序,因为TreeSet是有序集合并且具有与通常HashMap不同的某些顺序。每个SortedMap都必须知道如何对它所包含的元素进行排序。这可以通过两种方式完成:

  1. 您可以从Comparable<T>接口实现您的类。
  2. 您可以将自定义Comparator<T>添加到SortedMap

因此,您有三种方法可以修复它(可能更多,但其中三种 - 很明显(:

  1. 摆脱SortedMap,假设将SortedMap替换为Map,并将TreeMap替换为代码中的HashMap
  2. 将自定义比较器添加到您的passengerSet

    HashMap<String, Cruise> cruiseMap = new HashMap<String, Cruise>();
    SortedSet<Passenger> passengerSet = new TreeSet<Passenger>(new Comparator<Passenger>() {
        @Override
        public int compare(Passenger lhs, Passenger rhs) {
            return lhs.getFirstName().compareTo(rhs.getFirstName());
        }
    });
    Queue<Passenger> waitingList = new LinkedList<>();
    Cruise cruise = new Cruise("1", passengerSet, waitingList, false);
    cruiseMap.put("1", cruise);
    Passenger passenger = new Passenger("Smith", "J");
    cruiseMap.get("1").getPassengerSet().add(passenger);
    
  3. Passenger 类中实现 Comparable<T> 接口。

    public class Passenger implements Comparable<Passenger> {
        private String lastName = "";
        private String firstName = "";
        public Passenger()
        {
            lastName = "no last name yet";
            firstName = "no first name yet";
        }
        public Passenger(String lastName, String firstName)
        {
            this.lastName = lastName;
            this.firstName = firstName;
        }
        /**
         * @return the lastName
         */
        public String getLastName()
        {
            return lastName;
        }
        /**
         * @param lastName the lastName to set
         */
        public void setLastName(String lastName)
        {
        this.lastName = lastName;
        }
        /**
         * @return the firstName
         */
        public String getFirstName()
        {
            return firstName;
        }
        /**
         * @param firstName the firstName to set
         */
        public void setFirstName(String firstName)
        {
            this.firstName = firstName;
        }
        /* (non-Javadoc)
         * @see java.lang.Object#toString()
         */
        @Override
        public String toString()
        {
            return lastName + " " + firstName;
        }
        @Override
        public int compareTo(Passenger another) {
            return firstName.compareTo(another.firstName);
        }
    }
    

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