英雄我使用的新代码。我已经尝试过,如果我先声明了n,那不是我想要的。我需要知道行总数(n(并在我的模拟中使用该数字。但是,在变量声明中,我需要在阅读数据之前要减少xy(n(,如果这样做,则代码不会运行。
数据文件是随机模拟的正常数据的两列
让我们说这样的话
1 3
2 4
3 6
4 8
5 9
6 8
7 1
8 9
99 88
我尝试了以下代码来确定N,但它不起作用!
program reading
implicit none
integer,allocatable :: a(:,:)
integer :: pair(2)
integer :: unit, n, io,k
!!!variable declaration
real, dimension(1:n)::x,y
integer:: T, I1, I2, I3, i, j, dist
open(2, file = 'xyBVNData_R.txt', status = 'old', action = 'read')
n = 0
DO
READ(2,*,iostat=io)
IF (io/=0) EXIT
n = n + 1
END DO
CLOSE (2)
print*, n
DO i=1,n!!!
DO j=1,n!!
dist=0.0
DIST = dist+(sqrt((x(i)-x(j))**2 + (y(i)-y(j))**2))
ENDDO
ENDDO
!!! writing and saving
Do i= 1, n
write(*,*) i, x(i)
ENDDO
end program reading
您无法声明具有未知维度的变量"尺寸(1:n("。
此程序首先读取文件以确定行数:
program reading
implicit none
! variable declaration
real, dimension(:) ,allocatable :: x ,y
real :: dist
integer:: i, j ,n ,io
open(2, file = 'xyBVNData_R.txt', status = 'old', action = 'read')
n = 0
DO
READ(2,*,iostat=io)
IF (io/=0) EXIT
n = n + 1
END DO
print*, n
allocate( x(n) ,y(n) )
rewind(2)
DO i =1,n
READ(2,*) x(i),y(i)
END DO
dist=0.0
DO i=1,n
DO j=1,n
dist = dist + sqrt( (x(i)-x(j))**2 + (y(i)-y(j))**2 )
END DO
END DO
! writing and saving
DO i= 1, n
write(*,*) i, x(i)
END DO
end program reading
另一种替代方案(Fortran 2003(,它通过添加新元素在读取新线时添加新元素来重新关注x
和y
:
program reading
implicit none
! variable declaration
real, dimension(:) ,allocatable :: x ,y
real :: dist ,x_tmp ,y_tmp
integer:: i, j ,n ,io
open(2, file = 'xyBVNData_R.txt', status = 'old', action = 'read')
n = 0
allocate( x(0) ,y(0) )
DO
READ(2,*,iostat=io) x_tmp,y_tmp
x = [x,x_tmp]
y = [y,y_tmp]
IF (io/=0) EXIT
n = n + 1
END DO
print*, n
dist=0.0
DO i=1,n
DO j=1,n
dist = dist + sqrt( (x(i)-x(j))**2 + (y(i)-y(j))**2 )
END DO
END DO
! writing and saving
DO i= 1, n
write(*,*) i, x(i)
END DO
end program reading