我将此代码用作DFA确定性有限自动机,甚至可以接受1或0的输入
#include <stdio.h>
#define TOTAL_STATES 2
#define FINAL_STATES 1
#define ALPHABET_CHARCTERS 2
#define UNKNOWN_SYMBOL_ERR 0
#define NOT_REACHED_FINAL_STATE 1
#define REACHED_FINAL_STATE 2
enum DFA_STATES{q0,q1,q2,q3};
enum input{0,1};
int Accepted_states[FINAL_STATES]={q0};
char alphabet[ALPHABET_CHARCTERS]={'0','1'};
int Transition_Table[TOTAL_STATES][ALPHABET_CHARCTERS];
int Current_state=q0;
void DefineDFA()
{
Transition_Table[q0][0] = q3;
Transition_Table[q0][1] = q1;
Transition_Table[q1][0] = q2;
Transition_Table[q1][1] = q0;
Transition_Table[q2][0] = q1;
Transition_Table[q2][1] = q3;
Transition_Table[q3][0] = q0;
Transition_Table[q3][1] = q2;
}
int DFA(char current_symbol)
{
int i,pos;
for(pos=0;pos<ALPHABET_CHARCTERS; pos++)
if(current_symbol==alphabet[pos])
break;//stops if any character other than a or b
if(pos==ALPHABET_CHARCTERS)
return UNKNOWN_SYMBOL_ERR;
for(i=0;i<FINAL_STATES;i++)
if((Current_state=Transition_Table[Current_state][pos])
==Accepted_states[i])
return REACHED_FINAL_STATE;
return NOT_REACHED_FINAL_STATE;
}
int main(void)
{
char current_symbol;
int result;
DefineDFA(); //Fill transition table
printf("Enter a string with 'a' s and 'b's:n Press Enter Key to stopn");
while((current_symbol=getchar())!= 'n')
if((result= DFA(current_symbol))==UNKNOWN_SYMBOL_ERR)
break;
switch (result) {
case UNKNOWN_SYMBOL_ERR:printf("Unknown Symbol %c",
current_symbol);
break;
case NOT_REACHED_FINAL_STATE:printf("Not accepted"); break;
case REACHED_FINAL_STATE:printf("Accepted");break;
default: printf("Unknown Error");
}
printf("nnn");
return 0;
}
我收到此错误10:15:错误:数字常量之前的预期标识符 10:15:错误:数字常量之前的预期"}" 10:15:错误:数字常量之前的预期非限定 ID 10:18:错误:"}"标记之前的预期声明
枚举项必须是名称而不是值
enum input{AAA,BBB};
或
enum input{AAA=0,BBB};
或
enum input{AAA=0,BBB=1};
你的行:
enum input{0,1};
使用整数作为枚举值。这是不允许的。像这样:
enum input {n0, n1};
很好。使用枚举的全部意义在于,可以使用描述性标题代替数字。