跟踪哪个(Tweepy)过滤器捕获了一条推文

Question

我需要在Twitter上跟踪许多关键字，然后将推文发送到MongoDB。我将其用于我的代码：

我如何从Twitter的流api中消耗推文并将其存储在mongodb

中

import json
import pymongo
import tweepy
consumer_key = ""
consumer_secret = ""
access_key = ""
access_secret = ""
auth = tweepy.OAuthHandler(consumer_key, consumer_secret)
auth.set_access_token(access_key, access_secret)
api = tweepy.API(auth)

class CustomStreamListener(tweepy.StreamListener):
    def __init__(self, api):
        self.api = api
        super(tweepy.StreamListener, self).__init__()
        self.db = pymongo.MongoClient().test
    def on_data(self, tweet):
        self.db.tweets.insert(json.loads(tweet))
    def on_error(self, status_code):
        return True # Don't kill the stream
    def on_timeout(self):
        return True # Don't kill the stream

sapi = tweepy.streaming.Stream(auth, CustomStreamListener(api))
to_track = ['keyword1', 'keyword2', 'keyword3']
sapi.filter(track = to_track)

我有没有办法跟踪哪个关键字负责每条推文？（不在每个搜索中进行GREP搜索）

Answer 1

我不确定on_data函数如何工作，但是您可以使用on_status并执行以下类似的操作：

import tweepy
consumer_key = ''
consumer_secret = ''
access_key = ''
access_secret = ''

auth = tweepy.OAuthHandler(consumer_key, consumer_secret)
auth.set_access_token(access_key, access_secret)
api = tweepy.API(auth)

class CustomStreamListener(tweepy.StreamListener):    
    def on_status(self, status):
        tweet = status.text        
        words = tweet.split()
        if 'keyword1' in words:
            print "do something with keyword1"
            self.db.tweets.insert(json.loads(tweet))
        if 'keyword2' in words:
            print "do something with keyword2"
            self.db.tweets.insert(json.loads(tweet))
        if 'keyword3' in words:
            print "do something with keyword3"
            self.db.tweets.insert(json.loads(tweet))
sapi = tweepy.streaming.Stream(auth, CustomStreamListener(api))
to_track = ['keyword1', 'keyword2', 'keyword3']
sapi.filter(track = to_track)