我以前的问题包含2个问题,而不是将其缩小到1
aim
当用户选择三个变量以访问数据时,用户将能够单击一个按钮以更改该数据的详细信息。
SQL-数据库表(Schooldata)
+-----+--------+------------+------------+----------------+-----------+
| ID | Class | Teacher | YearMonth | Description | Status |
+-----+--------+------------+------------+----------------+-----------+
| 1 | Alpha | Sara | 2017/01 | Good & Clean | Pending |
+-----+--------+------------+------------+----------------+-----------+
| 2 | Alpha | Sara | 2017/01 | Has 30 Chairs | Pending |
+-----+--------+------------+------------+----------------+-----------+
| 3 | Alpha | Sara | 2017/01 | Has 30 Tables | Pending |
+-----+--------+------------+------------+----------------+-----------+
| 4 | Alpha | Sara | 2017/01 | 5 Subjects | Pending |
+-----+--------+------------+------------+----------------+-----------+
| 5 | Beta | John | 2016/11 | Big & Clean | Official |
+-----+--------+------------+------------+----------------+-----------+
| 6 | Beta | John | 2016/11 | New Student | Official |
+-----+--------+------------+------------+----------------+-----------+
| 7 | Beta | John | 2016/11 | Injured Student| Official |
+-----+--------+------------+------------+----------------+-----------+
| 8 | Beta | John | 2016/11 | 6 Subjects | Official |
+-----+--------+------------+------------+----------------+-----------+
网页
+---------------------------------------------------------------+
| |
| |>Select Class<| |>Select Teacher<| |>Select Year/Month<| |
| |
| (Search) |
| |
| |
|>>>>>>>>>>>>>>>>>>>>>>>>>>INPUT<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<|
| |
| {Class} {Teacher} {Description} |
| |
| |
| (Update) |
| |
+---------------------------------------------------------------+
传奇
下拉列表 - |>&lt; |
按钮 - ()
文本输入 - {}
网页描述
UPDATE 按钮将将所选数据的"状态"更改为"待处理"。因此,如果说用户搜索|beta |约翰|2016/11 |然后单击 update 按钮,该数据的"状态"将从"官方"更改为"待处理"
但是,如果工作人员搜索"状态"已经"待处理"的数据,则| alpha | sara | sara | 2017/01 |,更新按钮将被禁用。
html表
<!--Those data are setting for checking data existance in the database -->
<input type="hidden" name="class" value=" <?php echo $class; ?>" >
<input type="hidden" name="date" value=" <?php echo $getDate; ?>">
<input type="hidden" name="teacher" value=" <?php echo $teacher; ?>" >
<input type="hidden" id="inputStatus" name="status" value="">
更新按钮(HTML)
<td colspan="1" valign="bottom" align="left">
<button type="button" class="btn btn-lg update" id="btnUpdate" name="update"> Enable Re-Submit </button>
</td>
更新按钮函数(JavaScript)
$(function (){
$("button#btnUpdate").on('click', function (e){
e.preventDefault();
$("#inputStatus").val("update");
$.ajax({
type: 'post',
url: 'changeClassStatus.php'
});
}
}
changeclassstatus.php(php)
<?php
$class = trim($_POST['calss']);
$teacher = trim($_POST['teacher']);
$date = $_POST['date'];
$date = $date."/01";
$status = $_POST['status'];
$empId = $_POST['empId'];
if($status == 'update'])){
$sqlUpdate = mysqli_query($conn,"UPDATE SchoolData SET Status='Pending' WHERE (Class=$class AND Teacher=$teacher AND ID='".$id[$i]."' AND YEAR(MonthYear)= YEAR('$date') AND MONTH(MonthYear)= MONTH('$date'));";
$sqlExecute=$conn->query($sqlUpdate)or exit("Error code ({$conn->errno}): {$conn->error}");
echo "Data Status Changed";
}
?>
问题描述
我已经实施了这些代码,但它们没有更新搜索数据的状态。当我单击 update 按钮时,数据未更新,也不会发生任何事情(没有更改,没有回声消息)
其他注释
这个问题链接到PHP -SQL-禁用,根据数据隐藏或启用按钮。如果我的问题缺乏或不准确的信息或问题,请告诉我。谢谢
在您的if语句中让我们开始,但试图查看是否正确地将所有变量传递到您的查询中,您可以通过写作来做到这一点。
echo $class;
echo $teacher;
etc ....
在查询之前您的if语句中的内部。
我注意到$class = trim($_POST['calss']);
应该是"类"吗?或cals?
让我用您的代码本身向您解释
$("button#btnUpdate").on('click', function (e){
e.preventDefault();
$("#inputStatus").val("update");
$.ajax({
type: 'post',
url: 'changeClassStatus.php'
});
}
在服务器端,PHP期望从AJAX POST请求中的以下变量
$class = trim($_POST['calss']);
$teacher = trim($_POST['teacher']);
$date = $_POST['date'];
$date = $date."/01";
$status = $_POST['status'];
$empId = $_POST['empId'];
因此,您的ajax请求应在下面的语法中重新编写。
上面的AJAX请求不包含任何POST参数。您应该向其添加数据属性。请参阅下面的示例
$.ajax({
url: 'url',
type: 'GET',
data: { field1: "hello", field2 : "hello2"} ,
contentType: 'application/json;
charset=utf-8'
});
在jQuery ajax调用中,将字段变量传递给 data
属性,以json格式将php脚本使用$ _post获取字段变量值,将 type
用作post。
$.ajax({
url: 'changeClassStatus.php',
type: 'POST',
data: { calss: "hello", teacher : "hello2", date : "01/01/2017", status: "Active", empId : 12 },
contentType: 'application/json; charset=UTF-8',
success: function (response) {
console.log(response.status);
},
error: function () {
alert("error");
}
});
在这里,如果在AJAX调用中通过data
属性中传递,您的PHP脚本将获得值。在条件下,检查空变量,并仅在值不是空时进行更新。
<?php
$class = trim($_POST['calss']);
$teacher = trim($_POST['teacher']);
$date = $_POST['date'];
$date = $date."/01";
$status = $_POST['status'];
$empId = $_POST['empId'];
if((!empty($status) && $status == 'update') && !empty($class) && !empty($teacher) && !empty($date) && !empty($empId)){
$sqlUpdate = mysqli_query($conn,"UPDATE SchoolData SET Status='Pending' WHERE (Class=$class AND Teacher=$teacher AND ID='".$id[$i]."' AND YEAR(MonthYear)= YEAR('$date') AND MONTH(MonthYear)= MONTH('$date'));";
$sqlExecute=$conn->query($sqlUpdate)or exit("Error code ({$conn->errno}): {$conn->error}");
echo "Data Status Changed";
}
?>