下面是我的代码段,当我使用dojo stackContainer时,一旦启用了stack container.startup。请让我知道我要去哪里出错:
var linkOamTp = new TitlePane({
id:"linkOamTp",
preventCache : false,
open :true
});
registry.byId(containerWdg).addChild(linkOamTp);
domConstruct.create("div",{id:"linkOamStackControllerDiv"},linkOamTp.containerNode);
domConstruct.create("div",{id:"linkOamStackContainerDiv"},linkOamTp.containerNode);
var linkOamSc = new StackContainer({
style: "width: 100% !important; height: 98% !important",
id: "linkOamStackContainer"
},"linkOamStackContainerDiv");
var cp1 = new ContentPane({
title: "A-END",
style : " width:100%; height: 100%; ",
content : "content a"
});
linkOamSc.addChild(cp1);
var cp2 = new ContentPane({
title: "Z-END",
style : " width:100%; height:100%; ",
content : "content-b"
});
linkOamSc.addChild(cp2);
var controller = new StackController({containerId: linkOamSc.id},"linkOamStackControllerDiv");
linkOamSc.startup();
controller.startup();
您确定'linkoamsc.id'实际上正在返回" linkoamstackcontainer"?
通常,stackController与stackContainer(您已经完成)一起使用,并且StackController使用StackContainer的ID。
尝试将代码更改为
var controller = new StackController({containerId: "linkOamStackContainer"},"linkOamStackControllerDiv");
找到了解决方案,我刚刚称为" linkoamsc.resize()"