我试图将用户输入URL进入合并单元格的位置(&quot" f22:i22&quot"(它会自动格式化它为URL/超链接。因此,如果有人进入google.com
,它将使其成为https://www.google.com/
并验证它。
我有。(我几乎很肯定这是错误的(
Sub formaturl ()
if ishyperlink(value) then values (x,y) = format(value, "https:// .com")
End Sub
我已经看到了代码,您可以将超链接添加到下拉列表中。这不是我想要的,因为用户将添加他们的公司URL。
编辑:这是我能够工作的最终代码。我还修改了"超链接"。细胞样式是16个字体,没有下划线以使其更容易阅读。
Sub handlethingone(target As Range)
Dim ws As Worksheet
Dim xCell As Range
Dim prefixAddress As String
Dim suffixAddress As String
Set xCell = ActiveSheet.Range("F22")
Set ws = ActiveSheet
prefixAddress = "www."
suffixAddress = ".com"
With ws
If .Range("F22").Value <> vbNullString Then
If Not Left(.Range("F22").Value, 4) = prefixAddress Then
xCell.Parent.Hyperlinks.Add Anchor:=xCell, Address:="", SubAddress:= _
prefixAddress & xCell, TextToDisplay:=prefixAddress & xCell
End If
If Not Right(.Range("F22").Value, 4) = suffixAddress Then
xCell.Parent.Hyperlinks.Add Anchor:=xCell, Address:="", SubAddress:= _
xCell & suffixAddress, TextToDisplay:=xCell & suffixAddress
End If
End If
End With
With xCell.Font
.Name = ("Arial")
.Size = 16
.Color = RGB(0, 0, 0)
.Underline = xlUnderlineStyleNone
End With
With xCell.Font
.Name = ("Arial")
.Size = 16
.Color = RGB(0, 0, 0)
.Underline = xlUnderlineStyleNone
End With
End Sub
您可以尝试如下所示:
Option Explicit
Sub HyperlinkFormatter()
Dim ws As Worksheet
Dim xCell As Range
Dim prefixAddress As String
Dim suffixAddress As String
Set xCell = ActiveSheet.Range("F22")
Set ws = ActiveSheet
prefixAddress = "www."
suffixAddress = ".com"
With ws
If .Range("F22").value <> vbNullString Then
If Not Left(.Range("F22").value, 4) = prefixAddress Then
xCell.Parent.Hyperlinks.Add Anchor:=xCell, address:="", SubAddress:= _
prefixAddress & xCell, TextToDisplay:=prefixAddress & xCell
End If
If Not Right(.Range("F22").value, 4) = suffixAddress Then
xCell.Parent.Hyperlinks.Add Anchor:=xCell, address:="", SubAddress:= _
xCell & suffixAddress, TextToDisplay:=xCell & suffixAddress
End If
End If
End With
With xCell.Font
.ColorIndex = xlAutomatic
.Underline = xlUnderlineStyleNone
End With
With xCell.Font
.Underline = xlUnderlineStyleSingle
.Color = -4155132
End With
End Sub