以下查询需要大量时间返回两个不同数据库中的结果。有什么方法可以简化此查询?
WITH tblParent AS
(
SELECT *
FROM REFERENCES
WHERE referenced_id = 208593
UNION ALL
SELECT REFERENCES.*
FROM REFERENCES
JOIN tblParent ON REFERENCES.referenced_id = tblParent.entity_Id
)
SELECT DISTINCT(entity_Id)
FROM tblParent
WHERE entity_Id <> 208593 AND field_type = 'ChildField'
OPTION(MAXRECURSION 5)
这应该简化它:
WITH tblParent AS
(
SELECT entity_Id, 0 c
FROM [REFERENCES]
WHERE referenced_id = 208593
UNION ALL
SELECT r.entity_Id, 1
FROM [REFERENCES] r
JOIN tblParent
ON r.referenced_id = tblParent.entity_Id
)
SELECT DISTINCT entity_Id
FROM tblParent
WHERE c = 1
OPTION(MAXRECURSION 5)
通过检查C值,很明显它是一个子值。我假设此文本为所有孩子都有field_type ='Childfield'。
(引用是一个保留的单词,而独特的不是函数(
由于您仅对Child EntityID感兴趣,然后只需在递归CTE中选择您需要的字段即可。
WITH tblParent AS (
SELECT entity_Id, referenced_id as baseId
FROM [REFERENCES]
WHERE referenced_id = 208593
UNION ALL
SELECT t.entity_Id, cte.baseId
FROM tblParent cte
JOIN [REFERENCES] t
ON (t.referenced_id = cte.entity_Id
AND t.entity_Id <> cte.baseId -- to avoid a circular reference
)
WHERE t.field_type = 'ChildField'
)
SELECT DISTINCT entity_Id
FROM tblParent
WHERE entity_Id <> baseId
OPTION(MAXRECURSION 5)
,如果Referend_id上有索引,则可能需要仔细检查。