如何在列表视图上应用列表视图搜索过滤器后传递意图?

Question

我尝试在我的安卓应用程序中实现列表视图功能。我在列表视图项目上应用单击侦听器，它工作正常，数据很容易传递到另一个活动。但是我也在同一列表视图项目上使用搜索功能搜索工作正常，但是当我单击列表视图搜索项目时，搜索后它总是在列表视图中打开第一个项目，例如，如果我在列表视图中搜索汽车名称Cultus，它总是打开第一个项目。这是我的代码 适配器代码

公共类 CarsAdapter 扩展 BaseAdapter 实现 Filterable {

Context context;
LayoutInflater inflater;
List<Cars> modellist;
ArrayList<Cars> filterList;
private ValueFilter valueFilter;
ArrayList<Cars> carsArrayList ;
private ArrayList<Cars> mStringFilterList;
public CarsAdapter(){}
public CarsAdapter(Activity context, ArrayList<Cars> _Cars) {
super();
this.context = context;
this.carsArrayList = _Cars;
mStringFilterList =  _Cars;
this.inflater = (LayoutInflater) 
context.getSystemService(Context.LAYOUT_INFLATER_SERVICE);
getFilter();
}
@Override
public int getCount() {
return filterList.size();
}
@Override
public Object getItem(int position) {
return filterList.get(position);
}
@Override
public long getItemId(int position) {
return position;
}
@Override
public View getView(int position, View convertView, ViewGroup parent) {
if (convertView == null) {
LayoutInflater inflater = ((Activity) context).getLayoutInflater();
convertView = inflater.inflate(R.layout.cars_item, parent, false);
TextView carname = (TextView)
convertView.findViewById(R.id.carName);
TextView carmodal = (TextView)
convertView.findViewById(R.id.carModal);

TextView carPrice = (TextView)
convertView.findViewById(R.id.carprice);

TextView carstatus = (TextView)
convertView.findViewById(R.id.carStatus);
ImageView carimage = (ImageView)
convertView.findViewById(R.id.carimage);

carname.setText(carsArrayList.get(position).getCarname());
carmodal.setText(carsArrayList.get(position).getCarmodal());
carPrice.setText(carsArrayList.get(position).cardemand);
carstatus.setText(carsArrayList.get(position).carstatus);
return convertView;
}


@Override
public Filter getFilter() {
if(valueFilter==null) {
valueFilter=new ValueFilter();
}
return valueFilter;
}
private class ValueFilter extends Filter {
@Override
protected FilterResults performFiltering(CharSequence constraint) {
FilterResults results = new FilterResults();
if (constraint != null && constraint.length() > 0) {
filterList = new ArrayList<Cars>();
for (int i = 0; i < mStringFilterList.size(); i++) {
if ((mStringFilterList.get(i).getCarname().toUpperCase())
.contains(constraint.toString().toUpperCase())) {
Cars cars = new Cars();
cars.setCarname(mStringFilterList.get(i).getCarname());

cars.setCarmodal(mStringFilterList.get(i).getCarmodal());
cars.setCardemand(mStringFilterList.get(i).getCardemand());
cars.setCarstatus(mStringFilterList.get(i).getCarstatus());
//  cars.se(mStringFilterList.get(i).getId());
filterList.add(cars);
}
}
results.count = filterList.size();
results.values = filterList;
} else {
results.count = mStringFilterList.size();
results.values = mStringFilterList;
}
return results;
}
@SuppressWarnings("unchecked")
@Override
protected void publishResults(CharSequence constraint,
FilterResults results) {
carsArrayList = (ArrayList<Cars>) results.values;
notifyDataSetChanged();
}

}
}

Answer 1

在构造函数中添加以下内容：

this.filterList = _Cars;

试试这个过滤器：

@Override
public Filter getFilter() {
return new Filter() {
@Override
protected FilterResults performFiltering(CharSequence charSequence) {
String charString = charSequence.toString();
if (charString.isEmpty()) {
filterList = carsArrayList;
} else {
ArrayList<Cars> filteredL = new ArrayList<>();
for (Cars row : carsArrayList) {
// name match condition. this might differ depending on your requirement
// here we are looking for name or phone number match
if (row.getFlatName().toLowerCase().contains(charString.toLowerCase())) {
filteredL.add(row);
}
}
filterList = filteredL;
}
FilterResults filterResults = new FilterResults();
filterResults.values = filterList;
return filterResults;
}
@Override
protected void publishResults(CharSequence charSequence, FilterResults filterResults) {
filterList = (ArrayList<Cars>) filterResults.values;
notifyDataSetChanged();
}
};
}

现在，如果您在适配器上执行"getItem(position("，它会为您提供确切的对象