是否有任何方法可以预测当nhibernate生成sql时将为表生成什么别名?
理论上它应该是'this_', 'this_1_'等,这将是伟大的,但我刚刚发现,这是有点多的随机当我使用加入在映射。
例如在集成测试中,我得到这样的东西:
table1 this_
left outer join
table2 o this_1_
on this_.id=this_1_.t1id
left outer join
table3 this_2_
on this_.id=this_2_.t1id
left outer join
table4 this_3_
on this_.id = this_3_.t1id
left outer join
table5 somealiasbasedonrootentity_2_
on this_.id=somealiasbasedonrootentity_2_.t1id
但是当我在web服务器上运行相同的映射时…所有的别名都是一些别名,一些别名等
它不应该至少…更一致的吗?
使得在映射
中使用任何类型的'where'或'formula'变得非常困难(甚至不可能)。——edit:示例查询我想实现与映射
select
t1.a, t2.a, (select max(t3.value) where t3.id=t2.t3id)
from table1 t1
left join table2.t2 on t2.t1id=t1.id;
——edit这是(几乎是最新的)映射:我知道它很大,但我是为了报道的目的而制作的。(顺便说一下,这不是最近的版本)
public class ClaimHistoryMap : ClassMap<ClaimHistory>
{
public ClaimHistoryMap()
{
Table("wts_claim");
ReadOnly();
Not.LazyLoad();
Id(x => x.Id, "claimid");
Map(x => x.ClaimNo, "claimNo");
Map(x => x.DateCompleted, "ModificationDate");
Map(x => x.DateOfDispatch, "DateOfDispatch");
Map(x => x.DateProcessed, "ModificationDate");
Map(x => x.Status, "status");
Map(x => x.WorkOrderNo, "ServiceWorkOrder");
Map(x => x.SerialNo, "serialNo");
Map(x => x.IsEnabled, "bStatus");
Map(x => x.InvoiceNo, "InvoiceNo");
Map(x => x.ServiceCoverage).Formula(
@"(Select c.coveragename from wts_servicecoverage as c where c.servicecoverageid=servicecoverageid)");
Join("wts_site_info",x=>
{
x.Optional().KeyColumn("claimid");
x.Map(s => s.CustomerName, "CustomerName");
x.Map(s => s.CustomerAddress, "Address");
x.Map(s => s.CustomerCity, "City");
x.Map(s => s.CustomerPhone, "Phone");
x.Map(s => s.CustomerZip, "Zip");
x.Map(s => s.ReportComplaint, "Complaint");
x.Map(s => s.TechnicianName, "TechName");
x.Map(s => s.Model)
.Formula(@"(Select mo.Model from WTS_Product mo where mo.ProductId=this_1_.ProductId)");
x.Map(s => s.CustomerState)
.Formula(@"(Select st.statename from wts_state st where st.stateid=this_1_.state)");
});
Join("wts_grand_total", x =>
{
x.Optional().KeyColumn("claimid");
x.Map(s => s.TotalCharge, "total");
x.Map(s => s.FreightCharge, "Frieght");
x.Map(s => s.PartsCharge, "Parts");
x.Map(s => s.HandlingFee, "Handling");
x.Map(s => s.SalesTax, "Mix");
});
Join("wts_labour_travel", x =>
{
x.Optional().KeyColumn("claimid");
x.Map(s => s.TravelCharge).Formula("traveltotal+travelovertotal+MilageRegular+MilageOvertime+supmileagehour+supmileageoverhour");
x.Map(s => s.TravelTime).Formula("TravelHourRegular+TravelHourOvertime+suptravelhour+suptraveloverhour");
x.Map(s => s.LaborCharge).Formula("labortotal+laborovertotal");
x.Map(s => s.LaborTime).Formula("LaborHoursRegular+LaborHoursOvertime+suplaborhour+suplaboroverhour");
x.Map(s => s.TripsNo, "trips");
x.Map(s => s.TruckCharge).Formula(
"(select max(ltr.TruckRate) from wts_labour_travel_rate ltr where ltr.LabourTravelId = this_3_.LabourTravelId)");
});
Map(x => x.WasModified).Formula(
"(select count(comm.claim_id) from wts_claim_status comm where comm.claim_id=this_.claimid and comm.Status=3)");
References(x => x.User, "entryBy").Fetch.Join().Not.LazyLoad();
HasMany(x => x.PartNo).KeyColumn("claimid").Table("wts_general_part").Element("partNo");
HasMany(x => x.Repairs).KeyColumn("claimid").Table("wts_Claim_Resolution").Element("resolutionDesc");
}
}
您不需要在映射中引用别名,只需引用您感兴趣的属性即可。例如,如果你有一个FluentNHibernate映射到一个类,它有一个名为"SomeValue"的属性,你可以在映射中创建一个where限制,像这样:
Where("SomeValue = 1");
类似的事情也适用于XML文件映射。