这是 hwk 链接提示,可帮助解决任何问题。 请阅读以下内容以查看我的问题。 这只是了解我的问题是什么的信息
http://penguin.ewu.edu/cscd300/Spring_12/Assignments/prog2.html
使用队列和堆栈,以作业的形式,Im 给出一个家庭作业,基本上是一个输入文件并编写一个命令参数来计算运行时间。 IM 给出了如下所示的输入文件:
Media Player
100
Angry Birds
140
然后我们在 jgrasp 中输入一个参数,例如"jobs.txt 50 1",这意味着文本文件、时间片和延迟。(见上面的链接)下面是基于上面显示的示例输入的程序执行示例:
C:classescscd300queues>java QueueSimulation jobs.txt 50 1
Time Slice: 50
Latency: 1
Adding Jobs to Queue
--------------------
Media Player, 100 milliseconds to execute
Angry Birds, 140 milliseconds to execute
Begin Job Processing
--------------------
Executing Media Player, 100 milliseconds remaining
Executing Angry Birds, 140 milliseconds remaining
Executing Media Player, 50 milliseconds remaining
*Media Player finished, total time to execute was 153 milliseconds
Executing Angry Birds, 90 milliseconds remaining
*Angry Birds finished, total time to execute was 244 milliseconds
所有作业已完成!
这是我的代码:(下面有一个作业类,一个测试器和一个linkedqueue类,我用它来制作自己的带有enqueue和dequeue的类(hwk的一部分,我没有包括它,因为那是很多代码,只知道enqueue和dequeue是方法)我的问题在测试器中:
public class Job {
String jobName;
int runTime;
int remainTime;
int startTime;
//constructures
public Job() {
jobName = "";
runTime = 0;
remainTime = 0;
startTime = 0;
}
public Job(String _jobName, int _runTime) {
jobName = _jobName;
runTime = _runTime;
remainTime = _runTime;
startTime = 0;
}
}
public class QueueTester {
public static void main(String[] args) {
linkedQueue waitQ = new linkedQueue();
linkedQueue runQ = new linkedQueue();
String fileName = "no_fileName";
int slice = 0, timeSW=0;
if (args.length !=3)
throw new IllegalStateException("No command line arguments...n");
fileName = args[0];
slice = Integer.parseInt(args[1]);
timeSW = Integer.parseInt(args[2]);
System.out.println("nTime Slice: " + slice);
System.out.println("nLatency: " +timeSW + "n");
Job job = null;
try {
FileInputStream fstream = new FileInputStream(fileName);
DataInputStream in = new DataInputStream(fstream);
BufferedReader br = new BufferedReader(new InputStreamReader(in));
String strLine;
System.out.println("adding jobs to queue");
System.out.println("--------------------");
boolean first = true;
while ((strLine = br.readLine()) != null) {
if (job == null)
job = new Job("", 0);
strLine = strLine.trim();
if (strLine.startsWith("#")) continue;
if (strLine.length() == 0) continue;
if (first) {
job.jobName = strLine;
first = false;
} else {
job.runTime = Integer.parseInt(strLine);
job.remainTime = job.runTime;
job.startTime = 0;
System.out.println(job.jobName + ", " + job.runTime + "milliseconds to excecute.");
waitQ.enqueue(job); //enqueue
job = null;
first = true;
}
}
in.close(); //close the input stream
}
catch (Exception e) {
System.err.println("Error: " + e.getMessage());
}
Job waitJob;
System.out.println("nBegin Job Processing");
System.out.println("---------------------");
boolean done = false;
int elapsed = 0;
while (!done) {
while(!waitQ.isEmpty()) {
waitJob = (Job)waitQ.dequeue();//dequeue
runQ.enqueue(waitJob); //enqueue
}
Job runJob;
while (!runQ.isEmpty()) {
runJob = (Job)(runQ.dequeue());
System.out.println("excecuting [" +runJob.jobName + "] " + runJob.remainTime + "milliseconds remaining");
if (slice < runJob.remainTime) {
runJob.remainTime -= slice;
if (runQ.isEmpty() && waitQ.isEmpty())
elapsed += slice;
else
elapsed += (slice + timeSW);
waitQ.enqueue(runJob);
}else {
int num = runJob.runTime + timeSW + runJob.remainTime;
System.out.println("*" + runJob.jobName + ", total time to execute was " +num+ "milliseconds");
}
}
}
}
}
我的程序有效,但我的输出如下所示。我的问题是为什么它输出不正确?如果您能帮助我对我的测试器类进行更正以使输出匹配,那就太棒了。只需帮助我找到我的错误或我需要添加感谢的内容!:) *
Begin Job Processing
---------------------
excecuting [Media Player] 100milliseconds remaining
excecuting [Angry Birds] 140milliseconds remaining
excecuting [Media Player] 50milliseconds remaining
*Media Player, total time to execute was 151milliseconds
excecuting [Angry Birds] 90milliseconds remaining
excecuting [Angry Birds] 40milliseconds remaining
*Angry Birds, total time to execute was 181milliseconds
如果您查看代码 Once gain,您会注意到您永远不会更新作业的运行时。从作业剩余时间中减去时间片后,还应更新作业已执行的时间。
"愤怒的小鸟"运行了 50 毫秒(当还剩 90 毫秒时),但一旦你把这个作业排队回来,你就失去了这些信息。
编辑:如果你基本上希望我给你答案。以下是您需要添加的缺失位。
runJob.runtime += slice
(否则,您可以选择将每个作业的已用重新化为 0,并将 'runJob.runtime += 已用,因为已用已包含延迟)重新排入队列作业之前