ASIHTTPRequest login page

Question

我尝试制作一个iPhone应用程序，该应用程序可以登录到使用https保护用户信息的Web应用程序。现在我被困在登录页面中。通过我的应用程序登录时，我不知道如何在用户网站中查看真实帐户。即使我放错了帐户，我也只得到了 200 的回复。

这是我的代码：

- (IBAction)clickOK:(id)sender {
NSURL *url = [NSURL URLWithString:@"https://www.freelancer.com/users/login.php"];
ASIFormDataRequest *request = [ASIFormDataRequest requestWithURL:url];
[request setUseKeychainPersistence:YES];
[request setDelegate:self]; 
request.shouldPresentCredentialsBeforeChallenge = YES; 
[request setRequestMethod:@"POST"];
[request setPostValue:usernameField.text forKey:@"username"];
[request setPostValue:passwordField.text forKey:@"passwd"];

request.timeOutSeconds = 30; 
[request setDidFailSelector:@selector(requestLoginFailed:)];
[request setDidFinishSelector:@selector(requestLoginFinished:)];
[request startAsynchronous];
}

- (void)requestLoginFailed:(ASIHTTPRequest *)request
{
//notify user
UIAlertView *alert = [[UIAlertView alloc] initWithTitle:@"Error" message:@"Error sending request to the server" delegate:nil cancelButtonTitle:@"OK" otherButtonTitles:nil];
[alert show];
}
- (void)requestLoginFinished:(ASIHTTPRequest *)request
{
int statusCode = [request responseStatusCode];
NSString *statusMessage = [request responseStatusMessage];
NSLog(@"StatusCode: %d", statusCode);
NSLog(@"StatusMessage: %@", statusMessage);
}

谁能建议我如何检查本网站的真实帐户并保持用户登录？

感谢您的任何帮助

Answer 1

你已经异步启动了一些事情

[request startAsynchronous];

然后只是期望它立即返回一些东西：

NSLog(@"%@",[request responseString]);
NSLog(@"%d",[request responseStatusCode]);

你需要放这样的东西：

[request setDidFinishSelector:@selector(didFinishRequest:)];

然后将您的 NSLogs 和任何其他从响应中窃取的东西移动到该方法中。