我已经开始将PHP项目重新编码为OOP。在许多人中,我无法完成的一件事是如何制作动态选择列表。我有许多查找选择列表要制作。最好的方法是什么?
我制作了一个数据库对象类,其中包含我所有的通用数据库查询。我是在这里添加它们还是为它们上一个特殊的课程,该如何进行编码?
require_once("database.php");
class DatabaseObject {
protected static $table_name;
// find all from a specific table
public static function find_all(){
global $database;
return static::find_by_sql("SELECT * FROM ".static::$table_name);
}
// select all from a specific table
public static function find_all_from($table){
global $database;
return static::find_by_sql("SELECT * FROM " .$table);
}
// find all from a specific table
public static function find_by_id($id){
global $database;
$result_array = static::find_by_sql("
SELECT * FROM ".static::$table_name. " WHERE id = '{$id}' LIMIT 1");
// return the data only for the one user
return !empty($result_array) ? array_shift($result_array) : false;
}
// find using sql
public static function find_by_sql($sql=""){
global $database;
// return all data from sql
$result_set = $database->query($sql);
$object_array = array();
while($row = $database->fetch_array($result_set)){
$object_array[] = static::instantiate($row);
}
return $object_array;
}
protected static function instantiate($record){
$class_name = get_called_class();
$object = new $class_name;
foreach($record as $attribute=>$value){
if($object->has_attribute($attribute)){
$object->$attribute = $value;
}
}
return $object;
}
protected function has_attribute($attribute){
$object_vars = $this->attributes();
// here we only want to know if the key exist
// so we will return true or false
return array_key_exists($attribute, $object_vars);
}
protected function attributes() {
$attributes = array();
foreach(static::$db_fields as $field) {
if(property_exists($this,$field)) {
$attributes[$field]= $this->$field;
}
}
return $attributes;
}
protected function sanitised_attributes() {
global $database;
$clean_attributes = array();
foreach($this->attributes() as $key => $value){
$clean_attributes[$key] = $database->escape_value($value);
}
return $clean_attributes;
}
public function save() {
// A new object won't have an id yet
return isset($this->id) ? $this->update() : $this->create();
}
// create new
protected function create() {
global $database;
$attributes =$this->sanitised_attributes();
$sql = "INSERT INTO ".static::$table_name." (";
$sql .= join(", " ,array_keys($attributes));
$sql .= ") VALUES ( '";
$sql .= join("', '" ,array_values($attributes));
$sql .= "')";
if($database->query($sql)) {
$this->id = $database->insert_id();
return true;
} else {
return false;
}
}
// update details
protected function update() {
global $database;
$attributes =$this->sanitised_attributes();
$attribute_pairs = array();
foreach($attributes as $key => $value) {
$attribute_pairs[] = "{$key}='{$value}'";
}
$sql = "UPDATE " .static::$table_name. " SET ";
$sql .= join(", ",$attribute_pairs);
$sql .= " WHERE id=". $database->escape_value($this->id);
$database->query($sql);
return ($database->affected_rows() ==1) ? true : false ;
}
public function delete() {
global $database;
$sql = "DELETE FROM ".static::$table_name;
$sql .= " WHERE id =". $database->escape_value($this->id);
$sql .= " LIMIT 1";
$database->query($sql);
return ($database->affected_rows() ==1) ? true : false ;
}
}
我肯定会将"选择列表"作为对象建模,因为它具有可以封装的明确责任。我会继续将其与DatabaseObject
尽可能地脱钩,以使任何类别的更改都不会影响另一个类别。例如,请考虑:
class SelectList
{
protected $options;
protected $name;
public function __construct($name, $options)
{
$this->options = $options;
$this->name = $name;
}
public function render()
{
$html = "<select name='" . $this->name . "'>n";
foreach ($this->options as $option)
{
$html .= $option->render();
}
$html .= "</select>n";
return $html;
}
}
class SelectListOption
{
protected $label;
protected $value;
protected $isSelected;
public function __construct($label, $value, $isSelected = false)
{
//Assign the properties
}
public function render()
{
$html .= '<option value="' . $this->value . '"';
if ($this->isSelected)
{
$html .= ' selected="selected" ';
}
$html .= '>' . $this->label . "</option>n";
}
}
我喜欢以这种方式建模事物的一件事是,添加新功能(例如,为所选/未选择的项目或禁用属性的CSS样式)非常容易,因为您知道在哪个新功能所属的对象中。另外,拥有这种"小"对象使编写单元测试变得很容易。
hth
只需创建一个方法,该方法通过通过传递给该方法的关联数组进行迭代来返回html select/options视图...?这样的东西也许是:
public static function viewSelect($name = "select", $arr_options = array()) {
$html = "<select name='$name'>n";
foreach ($arr_options as $key => $val) {
$html .= "<option value='$key'>$val</option>n";
}
$html .= "</select>n";
return $html;
}
然后,只需将数据库查询之一的结果传递给此方法即可。您可以将此方法放入您想要的任何适当类中。
您还可以添加选定的选项功能
公共静态函数ViewSelect($ name =" select",$ arr_options = array(),$ selected){
$selectedhtml = ""; $html = "<select name='$name'>n"; foreach ($arr_options as $key => $val) { if($key == $selected) $selectedhtml = "selected"; $html .= "<option value='$key' $selectedhtml>$val</option>n"; } $html .= "</select>n"; return $html; }
public function get_posts()
{
$query="select * from tbl_posts";
$result= mysql_query($query);
$i=0;
while($data= mysql_fetch_assoc($result))
{
foreach($data as $key=>$value)
{
$info[$i][$key]=$value;
}
$i++;
}
return $info;
}