我把这个文件作为一个模块加载到Hugs,但是得到这个错误:
文件:错误。拥抱。hs:38 -输入语法错误(意外关键字"let")
data MetricUnit = Meter
| Liter
| KiloGram
deriving (Show, Eq)
data ImperialUnit = Yard
| Gallon
| Pound
deriving (Show, Eq)
data Measurement = MetricMeasurement Double MetricUnit
| ImperialMeasurement Double ImperialUnit
deriving (Show)
symbol :: MetricUnit -> String
symbol x
| x == Meter = "m"
| x == Liter = "L"
| x == KiloGram = "kg"
convert (MetricMeasurement x u)
| u==Meter = ImperialMeasurement (1.0936*x) Yard
| u==Liter = ImperialMeasurement (0.2642*x) Gallon
| u==KiloGram = ImperialMeasurement (2.2046*x) Pound
convert (ImperialMeasurement x u)
| u==Yard = MetricMeasurement (0.9144*x) Meter
| u==Gallon = MetricMeasurement (3.7854*x) Liter
| u==Pound = MetricMeasurement (0.4536*x) KiloGram
let fac n = if n == 0 then 1 else n * fac (n-1) --This line doesn't work
let m = MetricMeasurement 2 Meter
您不能在顶层使用let
语句。只需写入
fac n = if n == 0 then 1 else n * fac (n-1)
m = MetricMeasurement 2 Meter
删除let
:
fac n = if n == 0 then 1 else n * fac (n-1)
m = MetricMeasurement 2 Meter
正如其他人指出的那样,您不将let
用于顶级定义,而仅用于函数中的局部定义。
我已经回答了,因为我忍不住要指出,你可以通过使用模式匹配来改进很多代码。
对于symbol
,匹配可以在顶层进行:
symbol :: MetricUnit -> String
symbol Meter = "m"
symbol Liter = "L"
symbol KiloGram = "kg"
而对于其他两个,您可以使用case语句来匹配u
,如下所示:
convert (MetricMeasurement x u) = case u of
Meter -> ImperialMeasurement (1.0936*x) Yard
Liter -> ImperialMeasurement (0.2642*x) Gallon
KiloGram -> ImperialMeasurement (2.2046*x) Pound
和convert (ImperialMeasurement x u)
是相似的。