NHibernate标准连接多个枚举值



我有一个名为User的类,在这个类中有一个UserRole枚举值的集合。

public class User {
    ...
    public ICollection<UserRole> UserRoles { get; private set; }
    ...
}
[Flags]
public enum UserRole {
    Beginner = 1,
    Advanced = 2,
    Expert = 4,
    Admin = 8
}

UserUserRole关系是一个多对多关系,由三个表(tblUser、tblRole和tblUserRole只有userId和roleId)实现。HBM如下:

<hibernate-mapping xmlns="urn:nhibernate-mapping-2.2" default-lazy="false">
   <class name="User, SampleDll" table="tblUser">
   ...
   <bag name="UserRoles" table="tblUserRole" cascade="all-delete-orphan" fetch="join">
      <key column="UserId"/>
      <element column="RoleId" type="UserRole, SampleDll" />      
   </bag> 
   ...
   </class> 
</hibernate-mapping> 

现在我想创建一个与

具有相同语义的条件
select u.* from tblUser u 
left join tblUserRole ur on ur.UserId = u.UserId
where ur.RoleId = @USER_ROLE

是否有可能实现这样的标准(使用queryOver或分离的标准)没有单独的映射文件的UserRole enum?

提前感谢你的提示。

merck

你已经有了一个标志枚举,它基本上已经是一个值的集合。为此,您甚至不需要UserRoles和Roles表,只需在User中添加一个简单的列就足够了

[Flags]
public enum UserRoles {
    Beginner = 1,
    Advanced = 2,
    Expert = 4,
    Admin = 8
}
public virtual UserRoles Roles { get; private set; }
<property name="Roles" column="UserRoles"/>

当你真正想要的东西:

public class User {
    ...
    public virtual ICollection<UserRole> Roles { get; private set; }
    ...
}
public class UserRole {
    public virtual int Id { get; set; }
    ...
}
然后

<bag name="Roles" table="tblUserRole" cascade="none"> <!-- none because Roles are somewhat static not per user -->
   <key column="UserId"/>
   <many-to-many column="RoleId" class="UserRole, SampleDll" />      
</bag>
<hibernate-mapping xmlns="urn:nhibernate-mapping-2.2">
  <class name="UserRole" table="Roles">
    <id name="Id"/>
    <!--additional properties-->
  </class>
</hibernate-mapping>

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