我有一个名为User
的类,在这个类中有一个UserRole
枚举值的集合。
public class User {
...
public ICollection<UserRole> UserRoles { get; private set; }
...
}
[Flags]
public enum UserRole {
Beginner = 1,
Advanced = 2,
Expert = 4,
Admin = 8
}
User
到UserRole
关系是一个多对多关系,由三个表(tblUser、tblRole和tblUserRole只有userId和roleId)实现。HBM如下:
<hibernate-mapping xmlns="urn:nhibernate-mapping-2.2" default-lazy="false">
<class name="User, SampleDll" table="tblUser">
...
<bag name="UserRoles" table="tblUserRole" cascade="all-delete-orphan" fetch="join">
<key column="UserId"/>
<element column="RoleId" type="UserRole, SampleDll" />
</bag>
...
</class>
</hibernate-mapping>
现在我想创建一个与
具有相同语义的条件select u.* from tblUser u
left join tblUserRole ur on ur.UserId = u.UserId
where ur.RoleId = @USER_ROLE
是否有可能实现这样的标准(使用queryOver或分离的标准)没有单独的映射文件的UserRole
enum?
提前感谢你的提示。
merck
你已经有了一个标志枚举,它基本上已经是一个值的集合。为此,您甚至不需要UserRoles和Roles表,只需在User中添加一个简单的列就足够了
[Flags]
public enum UserRoles {
Beginner = 1,
Advanced = 2,
Expert = 4,
Admin = 8
}
public virtual UserRoles Roles { get; private set; }
<property name="Roles" column="UserRoles"/>
当你真正想要的东西:
public class User {
...
public virtual ICollection<UserRole> Roles { get; private set; }
...
}
public class UserRole {
public virtual int Id { get; set; }
...
}
然后<bag name="Roles" table="tblUserRole" cascade="none"> <!-- none because Roles are somewhat static not per user -->
<key column="UserId"/>
<many-to-many column="RoleId" class="UserRole, SampleDll" />
</bag>
<hibernate-mapping xmlns="urn:nhibernate-mapping-2.2">
<class name="UserRole" table="Roles">
<id name="Id"/>
<!--additional properties-->
</class>
</hibernate-mapping>