如何从选项菜单启动服务

Question

我想在点击选项菜单项时启动一项服务。

 public boolean onCreateOptionsMenu(Menu menu) {
    // TODO Auto-generated method stub
    menu.add("Help").setIcon(R.drawable.HelpActivity).setIntent(new Intent(this,HelpActivity.class));//this is activity intent .It works fine
    menu.add("Update Media").setIcon(R.drawable.update_icon).setIntent(new Intent(this,MediaUpdate.class));//this is service intent.It dose not works
return super.onCreateOptionsMenu(menu);
}

舱单

    </service>
            <service android:name="com.Dexter.otp.services.MediaUpdate" >
    </service>

点击更新媒体我得到日志错误

11-30 12:46:10.775: E/MenuItemImpl(4918): Can't find activity to handle intent;   ignoring
11-30 12:46:10.775: E/MenuItemImpl(4918): android.content.ActivityNotFoundException:  Unable to find explicit activity class   {com.Dexter.otp/com.Dexter.otp.services.MediaUpdate}; have you declared this activity in your AndroidManifest.xml?

似乎无法通过菜单项启动服务/广播。

Answer 1

如果不起作用，您也可以尝试设置onclicklistener并调用startService

menu.add("setting").setOnMenuItemClickListener(
            new OnMenuItemClickListener() {
                @Override
                public boolean onMenuItemClick(MenuItem arg0) {
                    [Activtyname].this.startService(new Intent(this, MediaUpdateService.class));
                    return false;
                }
            });