如何将 Bean 的交换设置为 ProducerTemplate

Question

我正在使用CamelTestSupport进行测试，

public class TestIntegrationBeanCtrlContrat extends CamelTestSupport {
@EndpointInject(uri = "mock:result")
protected MockEndpoint resultEndpoint;
@Produce(uri = "direct:start")
protected ProducerTemplate template;
@Override
protected RouteBuilder createRouteBuilder() {
    return new RouteBuilder() {
        @Override
        public void configure() {
          this.from("direct:start")
         .bean(MyClassA.class, "methodOfMyClassA").to("mock:result");
        }
    };
}
@Test
public void test_ControleBean_Integration() {
    this.template.sendBody(....);
 }

我正在尝试将另一个 bean 的主体放入生产者模板中，例如：

template.sendBody( bean(MyClassB.class, "methodOfMyClassB") )

可以做到吗？

一般来说，我该怎么做才能在生产中设置输入。

Answer 1

我不确定我是否理解您的需求，但是如果您想在路由过程中注入某些 bean 的结果，您应该使用 Camel Mock 注入 bean 进程（在您的示例中为 MyClassB.methodOfMyClassB（））：

@EndpointInject(uri = "mock:result")
protected MockEndpoint resultEndpoint;
@Produce(uri = "direct:start")
protected ProducerTemplate template;
@Override
protected RouteBuilder createRouteBuilder() throws Exception {
    return new RouteBuilder() {
        @Override
        public void configure() throws Exception {
            from("direct:start").bean("BeanA", "methodA").to("mock:beanB").to("mock:result");
        }
    };
}
@Test
public void test() throws Exception {
    MockEndpoint mock = getMockEndpoint("mock:beanB");
    mock.whenAnyExchangeReceived(new Processor() {
        public void process(Exchange exchange) throws Exception {
            // call the method of your class here
            exchange.getIn().setBody(MyClassB.methodOfMyClassB());
        }
    });
    template.sendBody("Your message body...");
    // check some results
    mock.assertIsSatisfied();
}