我的PSQL视图中有三个外来标识符。如何根据 NULL second_id 值的共同first_id将 NULL 替换为third_id值?
现在:
first_id | second_id | third_id
----------+-----------+----------
1 | | 11
1 | | 11
1 | | 11
1 | 22 | 22
2 | 33 | 33
3 | 44 | 44
4 | 55 | 55
5 | 66 | 66
6 | | 77
6 | | 77
6 | | 77
6 | | 77
6 | 88 | 88
应该是:
first_id | second_id | third_id
----------+-----------+----------
1 | 22 | 11
1 | 22 | 11
1 | 22 | 11
1 | 22 | 22
2 | 33 | 33
3 | 44 | 44
4 | 55 | 55
5 | 66 | 66
6 | 88 | 77
6 | 88 | 77
6 | 88 | 77
6 | 88 | 77
6 | 88 | 88
如何进行此更改?
非常感谢。我真的很感激。
second_id
实际上是对third_id
的CASE WHEN
修改。此修改是在视图中进行的。
视图:
View "public.my_view"
Column | Type | Modifiers | Storage | Description
-----------------------------+-----------------------------+-----------+----------+-------------
row_number | bigint | | plain |
first_id | integer | | plain |
second_id | integer | | plain |
third_id | integer | | plain |
first_type | character varying(255) | | extended |
date_1 | timestamp without time zone | | plain |
date_2 | timestamp without time zone | | plain |
date_3 | timestamp without time zone | | plain |
View definition:
SELECT row_number() OVER (PARTITION BY t.first_id) AS row_number,
t.first_id,
CASE
WHEN t.localization_key::text = 'rq.bkd'::text THEN t.third_id
ELSE NULL::integer
END AS second_id,
t.third_id,
t.first_type,
CASE
WHEN t.localization_key::text = 'rq.bkd'::text THEN t.created_at
ELSE NULL::timestamp without time zone
END AS date_1,
CASE
WHEN t.localization_key::text = 'st.appt'::text THEN t.created_at
ELSE NULL::timestamp without time zone
END AS date_2,
CASE
WHEN t.localization_key::text = 'st.eta'::text THEN t.created_at
ELSE NULL::timestamp without time zone
END AS date_3
FROM my_table t
WHERE (t.localization_key::text = 'rq.bkd'::text OR t.localization_key::text = 'st.appt'::text OR t.localization_key::text = 'st.eta'::text) AND t.first_type::text = 'thing'::text
ORDER BY t.created_at DESC;
下面是视图正在使用的表定义的链接 (my_table)。
https://gist.github.com/dankreiger/376f6545a0acff19536d
再次感谢您的帮助。
你可以通过以下方式获得它:
select a.first_id, coalesce(a.second_id,b.second_id), a.third_id
from my_table a
left outer join
(
select first_id, second_id from my_table
where second_id is not null
) b
using (first_id)
所以更新应该是:
update my_table a set second_id = b.second_id
from
(
select first_id, second_id from my_table
where second_id is not null
) b
where b.first_id = a.first_id and a.second_id is null
您无法UPDATE
基础表my_table
因为它没有second_id
列,因此应使视图按所需方式显示数据。对于 CTE,这相当简单:
CREATE VIEW my_view AS
WITH second (first, id) AS (
SELECT first_id, third_id
FROM my_table
WHERE t.localization_key = 'rq.bkd')
SELECT
row_number() OVER (PARTITION BY t.first_id) AS row_number,
t.first_id,
s.id AS second_id,
t.third_id,
t.first_type,
CASE
WHEN t.localization_key = 'rq.bkd' THEN t.created_at
END AS date_1,
CASE
WHEN t.localization_key = 'st.appt' THEN t.created_at
END AS date_2,
CASE
WHEN t.localization_key = 'st.eta' THEN t.created_at
END AS date_3
FROM my_table t
JOIN second s ON s.first = t.first_id
WHERE (t.localization_key = 'rq.bkd'
OR t.localization_key = 'st.appt'
OR t.localization_key = 'st.eta')
AND t.first_type = 'thing'
ORDER BY t.created_at DESC;
这假设my_table.localization_key = 'rq.bkd'
你只有 1 个third_id
值;如果没有,你应该添加适当的限定符,如 ORDER BY first_id ASC NULLS LAST LIMIT 1
或其他合适的过滤器。另请注意,CTE 是 JOIN
ed,而不是 LEFT JOIN
ed,假设始终存在没有 NULL
s 的有效对(first_id, third_id)
。