App与ModelChoiceField合作，但不与ModelMultipliplechoicefield合作

Question

我正在尝试在Django页面中检索用户输入数据。但是我无法选择多级字段。我尝试了多种替代方案，以免缓解。

• self.fields ['site']。querySet = forms.modelmultiplechoicefield(querySet = stites.object.all(((

• self.fields ['site'] = forms.modelchoicefield(queryset = stites.objects.filter(project_id = project_id((

• self.fields ['site']。querySet = forms.multipliplechoicefield(widget = forms.selectmultiple，choce = [(p.id，str(p(for p in sites.object.objects.filters.filters.filterss.filter(project_ID(= project_id((((

forms.py

类searchform(forms.form(：

class Meta:
    model= images
    fields=['site']
def __init__(self,*args,**kwargs):
    project_id = kwargs.pop("project_id")     # client is the parameter passed from views.py
    super(SearchForm, self).__init__(*args,**kwargs)
    self.fields['site'] = forms.ModelChoiceField(queryset=sites.objects.filter(project_id=project_id))

views.py

def site_list(请求，project_id(：

form = SearchForm(project_id=project_id)
site_list = sites.objects.filter(project__pk=project_id).annotate(num_images=Count('images'))
template = loader.get_template('uvdata/sites.html')
if request.method == "POST":
    image_list=[]
    form=SearchForm(request.POST,project_id=project_id)
    #form=SearchForm(request.POST)
    #site_name=request.POST.get('site')
    if form.is_valid():
        site_name=form.cleaned_data.get('site')
        print(site_name)

我希望获得一个多选择字段，但最终会遇到此错误：

异常值：

'站点'

异常位置：/home/clyde/downloads/new/automatic_annotator_tool/django_app/search/search/forms.py in init ，第18行(第18行：self.fields ['site']。querySet = forms.multipliplechoicefield(widget = forms.selectmultiple，choce = [(p.id，str(p((p in sites.object.objects.filters.filters.filter(project_id = project_id = project_id = project_id = project_id =((((

Answer 1

您无法正确定义您的表格。该文档向您展示了如何执行此操作。

在您的情况下，这将是这样的：

class SearchForm(forms.Form):
    site = forms.ModelMultipleChoiceField(queryset=Sites.object.none())
    def __init__(self,*args,**kwargs):
        project_id = kwargs.pop("project_id")
        super(SearchForm, self).__init__(*args,**kwargs)
        self.fields['site'].queryset = Sites.objects.filter(project_id=project_id))

您似乎也使常规Form和ModelForm混淆，因为Meta.model仅在ModelForm中使用，而您使用的是常规Form。我建议您在继续之前阅读文档的差异。