UIDatePicker 返回当前日期未选择日期

Question

我有一个UIDatePicker，我按照下面的代码打印选定的日期。但是，它不会打印所选日期，只会打印当前日期。

@objc func setupDiscoverButton() {
let cell = Bundle.main.loadNibNamed("FirstTableViewCell", owner: self, options: nil)?.first as! FirstTableViewCell
// Date
let sessionDate = cell.datePicker.date
print("date: (sessionDate)")
}

这是我为我的UIDatePicker下定义的地方。

func tableView(_ tableView: UITableView, cellForRowAt indexPath: IndexPath) -> UITableViewCell {
let cell = Bundle.main.loadNibNamed("FirstTableViewCell", owner: self, options: nil)?.first as! FirstTableViewCell
// Date & time picker
cell.datePicker.minimumDate = Date()
cell.datePicker.timeZone = TimeZone.current
// Discover button
cell.discoverButton.addTarget(self, action: #selector(setupDiscoverButton), for: .touchUpInside)
return cell
}

Answer 1

获取日期选择器的更改，请收听datePickerChanged

datePicker.addTarget(self, action: #selector(datePickerChanged(picker:)), for: .valueChanged)

所以你的细胞将是

func tableView(_ tableView: UITableView, cellForRowAt indexPath: IndexPath) -> UITableViewCell {
let cell = Bundle.main.loadNibNamed("FirstTableViewCell", owner: self, options: nil)?.first as! FirstTableViewCell
// Date & time picker
cell.datePicker.minimumDate = Date()
cell.datePicker.timeZone = TimeZone.current
cell.datePicker.addTarget(self, action: #selector(datePickerChanged(picker:)), for: .valueChanged)
// Discover button
cell.discoverButton.addTarget(self, action: #selector(setupDiscoverButton), for: .touchUpInside)
return cell
}
@objc func datePickerChanged(picker: UIDatePicker) {
print(picker.date)
}