当数据更新时，如何更新QABSTRACTITEMMODEL视图

Question

我使用Qt example for QAbstractItemModel，然后尝试将Item更新为给定的index。

我尝试使用emit DataChanged，但它不起作用，视图未更新。

这是一个示例：

我想要的：当您单击按钮时，它将在索引0 上更新数据，动物的type将被更改，它将变成a 狮子。

#include <QAbstractListModel>
#include <QStringList>
#include <qqmlcontext.h>
//![0]
class Animal
{
public:
    Animal(const QString &type, const QString &size);
//![0]
    QString type() const;
    QString size() const;
    void setType(QString q) {
        m_type = q;
    }
private:
    QString m_type;
    QString m_size;
//![1]
};
class AnimalModel : public QAbstractListModel
{
    Q_OBJECT
public:
    Q_INVOKABLE void test() ;
    void setName(const QString &name);
    enum AnimalRoles {
        TypeRole = Qt::UserRole + 1,
        SizeRole
    };
    AnimalModel(QObject *parent = 0);
//![1]
//!
//!
    void setContext(QQmlContext *ctx) {
        m_ctx = ctx;
    }
    void addAnimal(const Animal &animal);
    int rowCount(const QModelIndex & parent = QModelIndex()) const;
    QVariant data(const QModelIndex & index, int role = Qt::DisplayRole) const;
    QHash<int, QByteArray> roleNames() const;
protected:
private:
    QList<Animal> m_animals;
    QQmlContext*  m_ctx;
signals:
    void dataChanged(const QModelIndex & topLeft, const QModelIndex & bottomRight);
//![2]
};
//![2]

model.h

#include "model.h"
#include "qDebug"
Animal::Animal(const QString &type, const QString &size)
    : m_type(type), m_size(size)
{
}
QString Animal::type() const
{
    return m_type;
}
QString Animal::size() const
{
    return m_size;
}


AnimalModel::AnimalModel(QObject *parent)
    : QAbstractListModel(parent)
{
}
void AnimalModel::addAnimal(const Animal &animal)
{
    beginInsertRows(QModelIndex(), rowCount(), rowCount());
    m_animals << animal;
    endInsertRows();
}
void AnimalModel::test() {
  m_animals[0].setType("Lion");
  emit dataChanged(QModelIndex(),QModelIndex());
  //I also tried:
  QModelIndex topLeft = createIndex(0,0);
  emit dataChanged(topLeft, topLeft);

 }
int AnimalModel::rowCount(const QModelIndex & parent) const {
    Q_UNUSED(parent);
    return m_animals.count();
}
QVariant AnimalModel::data(const QModelIndex & index, int role) const {
    if (index.row() < 0 || index.row() >= m_animals.count())
        return QVariant();
    const Animal &animal = m_animals[index.row()];
    if (role == TypeRole)
        return animal.type();
    else if (role == SizeRole)
        return animal.size();
    return QVariant();
}
//![0]
QHash<int, QByteArray> AnimalModel::roleNames() const {
    QHash<int, QByteArray> roles;
    roles[TypeRole] = "type";
    roles[SizeRole] = "size";
    return roles;
}
//![0]

model.cpp

#include "model.h"
#include <QGuiApplication>
#include <qqmlengine.h>
#include <qqmlcontext.h>
#include <qqml.h>
#include <QtQuick/qquickitem.h>
#include <QtQuick/qquickview.h>
//![0]
int main(int argc, char ** argv)
{
    QGuiApplication app(argc, argv);
    AnimalModel model;
    model.addAnimal(Animal("Wolf", "Medium"));
    model.addAnimal(Animal("Polar bear", "Large"));
    model.addAnimal(Animal("Quoll", "Small"));
    QQuickView view;
    view.setResizeMode(QQuickView::SizeRootObjectToView);
    QQmlContext *ctxt = view.rootContext();
    ctxt->setContextProperty("myModel", &model);
//![0]
    view.setSource(QUrl("qrc:view.qml"));

    view.show();
    return app.exec();
}

main.cpp

import QtQuick 2.0
import QtQuick 2.4
import QtQuick.Controls 1.3
import QtQuick.Window 2.2
import QtQuick.Dialogs 1.2
import QtQuick.Layouts 1.2
import QtQml.Models 2.1
import QtQuick.Controls.Styles 1.2

//![0]
ListView {
    width: 200; height: 250
    model: myModel
    delegate: Text { text: "Animal: " + type + ", " + size }
    MouseArea {
        anchors.fill: parent
        cursorShape: Qt.PointingHandCursor
        onClicked: {
        }
    }
    Button {
        anchors.bottom: parent.bottom
        width:50; height:50
        text:"click"
        onClicked: {
            myModel.test()
        }
    }
}
//![0]

view.qml

您知道为什么它不起作用吗？非常感谢！

Answer 1

不要重新定义子类中的信号。

删除以下行(在模型中(，它应按预期工作：

signals:
    void dataChanged(const QModelIndex & topLeft, const QModelIndex & bottomRight);

此外，调用dataChanged()时，您必须指定有效的QModelIndex。这是正确的：

  // I also tried:
  QModelIndex topLeft = createIndex(0,0);
  emit dataChanged(topLeft, topLeft);

Answer 2

您需要创建高级索引和右下索引，并发出datachanged。此更新所有模型数据。

QModelIndex topLeft = createIndex(0,0);
QModelIndex bottomRight = createIndex( rows count ,0);
emit dataChanged( topLeft, bottomRight );