我使用以下代码从表中删除条目 我想做的是检查是否从表中删除了任何值。如果删除一个值,脚本应打印成功,否则为 false。这就是我迄今为止所取得的成就。请帮忙
<?PHP
$mysqli = new mysqli("SQLHOST.COM","CLIENT","PASSWORD", "DNAME", 1234);
if ($mysqli->connect_errno) {
printf("Connect failed: %sn", $mysqli->connect_error);
exit();
}
else
{
printf("cONN Sucees");
if ($result = $mysqli->query("DELETE FROM ktable WHERE code='value'")) {
printf("Select returned %d rows.n", $result->num_rows);
printf($result->num_rows);
$result->close();
}
}
?>
删除需要返回的内容是affected_rows
http://www.php.net/manual/en/mysqli.affected-rows.php
您需要替换的内容
if ($result = $mysqli->query("DELETE FROM ktable WHERE code='value'")) {
printf("Select returned %d rows.n", $result->num_rows);
printf($result->num_rows);
$result->close();
}
工作代码
$value = ""; // Set To any Value
$mysqli = new mysqli ( "SQLHOST.COM", "CLIENT", "PASSWORD", "DNAME", 1234 );
if ($mysqli->connect_errno) {
printf ( "Connect failed: %sn", $mysqli->connect_error );
exit ();
} else {
printf ( "cONN Sucees" );
if ($mysqli->query (sprintf ( "DELETE FROM ktable WHERE code='%s'", mysqli_real_escape_string ( $mysqli, $value ) ) )) {
printf ( "Affected Rows %d rows.n", $mysqli->affected_rows );
}
}
你应该有一个工作输出