import numpy as np
import scipy.optimize as spo
def function(x,y):
return (np.sin(x*y+y)*np.exp(-1*(x**2+y**2)))**-1
xi=[0,0]
answer=spo.fmin(function,xi)
print 'the answer is', answer
我正在尝试最小化此功能。但是运行它会带来
TypeError: function() takes exactly 2 arguments (1 given)
scipy.optimize.fmin(func, x0, args=(), xtol=0.0001, ftol=0.0001, maxiter=None, maxfun=None, full_output=0, disp=1, retall=0, callback=None)
参数函数是可调用func(x,*args)
在这种情况下,fmin
使用一个参数调用function
- x
(即xi
(。第二个参数必须作为args
参数传递。
xi = 0
args = (0,)
answer = spo.fmin(function, x0=xi, args=args)
http://docs.scipy.org/doc/scipy-0.16.0/reference/generated/scipy.optimize.fmin.html
您的意图是最小化 2 个以上的变量("x"、"y"(,还是只减少一个变量(将"y"作为额外参数(?
def fn1(x, y):
# x is minimization variable
# y is extra argument
return (np.sin(x*y+y)*np.exp(-1*(x**2+y**2)))**-1
def fn2(xy):
# xy is minimization variable; assumed to be 2 elements
x,y = xy
return (np.sin(x*y+y)*np.exp(-1*(x**2+y**2)))**-1
fmin
个变量;失败
In [35]: optimize.fmin(fn1, x0=0, args=(0,))
Warning: Maximum number of function evaluations has been exceeded.
Out[35]: array([ 0.])
fmin
2 元素数组(x0
和函数(;返回 2 元素数组。
In [38]: optimize.fmin(fn2, x0=np.array([0,0]))
Optimization terminated successfully.
Current function value: 2.227274
Iterations: 64
Function evaluations: 121
Out[38]: array([ 0.29782369, 0.62167083])