我的数据如下：
8/29/2013<tab>1<tab>name<tab>aaaaaaaaaaa<tab>12
8/29/2013<tab>22<tab>asd<tab>asd<tab>123
8/29/2013<tab>23<tab>xycabc<tab>asd<tab>12
我需要这样的东西：
RECEIVED on:8/29/2013 FROM:name AMOUNT:12
RECEIVED on:8/29/2013 FROM:asdAMOUNT:123
我试过这个：
Dim rvsr As New IO.StreamReader(vcFile)
Dim vText As String
Dim vstring(-1) As String
p1 = " "
Dim vData As String = ""
While rvsr.Peek <> -1
vText = rvsr.ReadLine()
vstring = vText.Split(p1)
vData = vData + vbCrLf + "RECEIVED ON: " + vstring(0) + " FROM: " + vstring(1) + " AMOUNT: " + vstring(2)
End While
RichTextBox_WD.Text = vData
rvsr.Close()
如果不向我们展示您得到了什么，我无法确定到底发生了什么。但在查看您的代码时，我认为问题与您如何使用Split有关。我已经使用vbTab常量和使用字符串分隔符的String.Split方法修改了您的代码，以适应控制台应用程序，看看这是否是您想要的。
Imports System.IO
Module Module1
Sub Main()
Dim vText As String
Dim vstring(-1) As String
Dim p1 As String() = {vbTab} 'Note I am using a string array and the vbTab Constant
Dim vData As String = ""
Using rvsr As New StreamReader("C:\temp\source.txt")
While rvsr.Peek <> -1
vText = rvsr.ReadLine()
vstring = vText.Split(p1, StringSplitOptions.RemoveEmptyEntries) 'I am also using the option to remove empty entries a
vData = vData + vbCrLf + "Recieved On:" + vstring(0) + " From:" + vstring(2) + " Amount:" + vstring(4)
End While
End Using
Console.Write(vData)
Console.ReadLine()
End Sub
End Module
RichTextBox_WD.Text = String.Join(vbCrLf, File.ReadLines(vcFile).Select(Function(line)
Dim format = "RECEIVED ON: {0} FROM: {1} AMOUNT {2}"
Dim fields = line.Split(vbTab)
Return String.Format(format, fields(0), fields(1), fields(2))
End Function)
我更喜欢在IEnumerable<T>上创建一个Joined扩展方法，该方法封装String.Join（采用分隔符和可选的转换委托），在String上创建Formatted扩展方法，封装String.Format:
RichTextBox_WD.Text = File.ReadLines(vcFile).Joined(vbCrLf, Function(line)
Dim format = "RECEIVED ON: {0} FROM: {1} AMOUNT {2}"
Dim fields = lines.Split(VbTab)
Return format.Formmatted(fields(0), fields(1), fields(2))
End Function)