Symfony authentification : bad credentials

Question

我创建了一个身份验证表单，当我尝试登录时，出现错误"凭据无效"。我用error.messageKey检查了，问题不是来自用户名，所以问题必须来自密码。

我

到处看，我看不出有什么问题。你有什么想法吗？

提前致谢

security:
    hide_user_not_found: false
    encoders:
        AppEntityUtilisateur:
            algorithm: bcrypt
            cost: 5
    providers:
        in_memory: { memory: ~ }
        in_database:
            entity:
                class: AppEntityUtilisateur
                property: mail
    firewalls:
        dev:
            pattern: ^/(_(profiler|wdt)|css|images|js)/
            security: false
        main:
             anonymous: true
            provider: in_database
            form_login:
                login_path: login
                check_path: login
                default_target_path: home

和登录.twig

                <form action="{{ path('login') }}" method="POST">
                    <div class="form-group" id="formMail">
                        <label for="email">Email :</label>
                        <input type="email" class="form-control" id="email" placeholder="[e-mail]" required name="_username">
                        <span class="" id="spanMail"></span>
                        <span class="" id="spanErrMail"></span>
                    </div>
                    <div class="form-group" id="formMdp">
                        <label for="pwd">Mot de passe :</label>
                        <input type="password" class="form-control" id="pwd" placeholder="******" required name="_password">
                        <span class="" id="spanMdp"></span>
                        <span class="" id="spanErrMdp"></span>
                    </div>

用户实体

/**
 * @ORMEntity(repositoryClass="AppRepositoryUtilisateurRepository")
 * @UniqueEntity(
 * fields={"mail"},
 * message="Adresse mail déjà utilisée")
 */
 class Utilisateur implements UserInterface
{
/**
 * @ORMId()
 * @ORMGeneratedValue()
 * @ORMColumn(type="integer")
 */
private $id;
/**
 * @ORMColumn(type="string", length=255)
 */
private $nom;
/**
 * @ORMColumn(type="string", length=255)
 */
private $prenom;
/**
 * @ORMColumn(type="string", length=255)
 * @AssertEmail(
 *     message = "L'e-mail {{ value }} n'est pas valide ")
 */
private $mail;
/**
 * @ORMColumn(type="string", length=255)
 * @AssertLength(min="5", minMessage="Le mot de passe doit faire au moins 5 caractères")
 */
private $mdp;
public function getId(): ?int
{
    return $this->id;
}
public function getNom(): ?string
{
    return $this->nom;
}
public function setNom(string $nom): self
{
    $this->nom = $nom;
    return $this;
}
public function getPrenom(): ?string
{
    return $this->prenom;
}
public function setPrenom(string $prenom): self
{
    $this->prenom = $prenom;
    return $this;
}
public function getMail(): ?string
{
    return $this->mail;
}
public function setMail(string $mail): self
{
    $this->mail = $mail;
    return $this;
}
public function getMdp(): ?string
{
    return $this->mdp;
}
public function setMdp(string $mdp): self
{
    $this->mdp = $mdp;
    return $this;
}
public function getPassword(){}
public function getUsername(){
    return $this->mail;
}
public function eraseCredentials(){}
public function getSalt(){
    return '';
}
public function getRoles()
{
    return ['ROLE_USER'];
}
}

Answer 1

我找到了我的神秘感。我使用自己的函数名称来获取电子邮件和密码。

我应该实现getUsername（）和getPassword（）。

public function getMdp(): ?string
{
    return $this->mdp;
}
public function setMdp(string $mdp): self
{
    $this->mdp = $mdp;
    return $this;
}
public function getPassword(){
    return $this->mdp;
}
public function getUsername(){
    return $this->mail;
}