如何从aplay -l的字符串输出中获取值1,0

Question

我有这个字符串输出，我试图通过删除所有其余的来获得输出值:1,0。

。

$ aplay -l | grep "C-Media USB Audio Device"
card 1: Device [C-Media USB Audio Device], device 0: USB Audio [USB Audio]
$ aplay -l | grep "C-Media USB Audio Device" | awk '{print $2}'
1:
$ aplay -l | grep "C-Media USB Audio Device" | awk '{print $9}'
0:

但是如何立即获得值为1,0 ?即使字符串稍微大一点，但有card和device在哪里?

例如:wrong

$ aplay -l
**** List of PLAYBACK Hardware Devices ****
card 0: PCH [HDA Intel PCH], device 0: CA0132 Analog [CA0132 Analog]
  Subdevices: 0/1
  Subdevice #0: subdevice #0
card 0: PCH [HDA Intel PCH], device 3: HDMI 0 [HDMI 0]
  Subdevices: 1/1
  Subdevice #0: subdevice #0
card 1: Device [C-Media USB Audio Device], device 0: USB Audio [USB Audio]
  Subdevices: 1/1
  Subdevice #0: subdevice #0
card 2: NVidia [HDA NVidia], device 3: HDMI 0 [HDMI 0]
  Subdevices: 1/1
  Subdevice #0: subdevice #0
$ aplay -l | grep "HDA NVidia" | perl -anE 's/://g, say for $t="$F[1],$F[8]"'
2,0
$ aplay -l | grep "HDA Intel PCH" | perl -anE 's/://g, say for $t="$F[1],$F[8]"'
0,CA0132
0,HDMI
$ aplay -l | grep "C-Media USB Audio Device" | perl -anE 's/://g, say for $t="$F[1],$F[8]"'
1,0

Answer 1

aplay -l | grep "C-Media USB Audio Device" | perl -anE 's/://g, say for $t="$F[1],$F[8]"'

对于其他设备，它删除[]和:之间的所有字符，

aplay -l | grep "C-Media USB Audio Device" | perl -nE 's/ [.*?] | : //xg; say join",",(split)[1,5];'