数组未定义偏移量与 PHP

Question

<?php
$ar = Array (
[0] => Array ( [id] => 1 [social_id] => [role_id] => 0 [name] => [first_name] => Jimmy [last_name] => rathore [gender] => male [dob] => 06-02-1992 [language] => english [location] => xyz [address] => xyz [email] => [e-mail] [phone] => 9876543210 )

[1] => Array ( [id] => 3 [social_id] => [role_id] => 0 [name] => [first_name] => Dev [last_name] => Smith [gender] => [dob] => [language] => [location] => xyz [address] => xyz [email] => [e-mail] [phone] => 7838344344 )
[2] => Array ( [id] => 4 [social_id] => [role_id] => 0 [name] => [first_name] => Col [last_name] => Manon [gender] => male [dob] => 02-02-2017 [language] => english [location] => London [address] => ABCD [email] => [e-mail] [phone] => 7894561230)
) ;

$array = Array (
[0] => Array ( [id] => 1 [sm_id] => 1 [field_name] => first_name [value] => G2 [created_at] => 2017-02-24 11:05:03 [updated_at] => 2017-02-24 11:05:03 [deleted_at] => )
);
$arr = array();
foreach($row=0; $row<count($ar); $row++){
foreach($col=0; $col<count($array); $col++){
if($ar['0']['id'] == $array['0']['id']){
$arr['first_name'] = $ar['0']['first_name'];
$arr['last_name'] = $ar['0']['last_name'];
$arr['email'] = $ar['0']['email'];
$arr['phone'] = $ar['0']['phone'];
}
}
}
print_r($arr);die;
?>

我想将数据从一个数组映射到另一个数组，基于 $ar

['0]['id'] 和 $array['0']['sm_id']如果$ar的 ID 与$array的 sm_id 匹配，则推送到一个数组及其值，我如何实现相同的目标。 请建议

Expected result
Array( [id] => 1 [first_name] => Jimmy [last_name] => rathore [gender] => male [dob] => 06-02-1992 [language] => english [location] => xyz [address] => xyz [email] => [e-mail] [phone] => 9876543210 );

Answer 1

你可以这样做，因为原始数组是$ar，并且具有sm_id值的数组$array：

// Create a hash of all sm_id values to be found
$ids = array_flip(array_column($array, "sm_id"));
// filter the original array to get only those with an id value in that hash
$arr = array_filter($ar, function ($row) use ($ids) {
return isset($ids[$row["id"]]);
});
print_r ($arr);