当我单击时,我正在尝试在backticks中运行onclick函数。
backticks:
socket.onmessage = function(event){
console.log(event.data);
const data = JSON.parse(event.data);
data.map((person)=>{
console.log(person)
$("#unknown-persons").append(`
<div class="media p-l-5">
<div class="pull-left">
<img width="40" src="${person.image}" alt="">
</div>
<div class="media-body">
<small class="text-muted">${new Date(parseInt(person.time))}</small><br/>
<a data-toggle="modal" href="#modal-unknown-person" onclick="labelingToUser(person)">${person.name} ${person.lastname}</a>
</div>
</div>
`)
})
}
on Click函数:
function labelingToUser(){}
,但我无法将人对象作为参数传递给我的onclik函数。我该怎么办?
人不是全局对象,因此无法访问函数。
尝试这个
var personglobal;
socket.onmessage = function(event){
console.log(event.data);
const data = JSON.parse(event.data);
data.map((person)=>{
personglobal = person;
console.log(person)
$("#unknown-persons").append(`
<div class="media p-l-5">
<div class="pull-left">
<img width="40" src="${person.image}" alt="">
</div>
<div class="media-body">
<small class="text-muted">${new Date(parseInt(person.time))}</small><br/>
<a data-toggle="modal" href="#modal-unknown-person" onclick="labelingToUser(personglobal)">${person.name} ${person.lastname}</a>
</div>
</div>
`)
})
}
您可以使用 JSON.stringify(person
)方法转换对象ot json字符串然后将其传递到呼叫如下:
socket.onmessage = function(event){
console.log(event.data);
const data = JSON.parse(event.data);
data.map((person)=>{
console.log(person)
$("#unknown-persons").append(`
<div class="media p-l-5">
<div class="pull-left">
<img width="40" src="${person.image}" alt="">
</div>
<div class="media-body">
<small class="text-muted">${new Date(parseInt(person.time))}</small><br/>
<a data-toggle="modal" href="#modal-unknown-person" onclick="labelingToUser(${JSON.stringify(person)})">${person.name} ${person.lastname}</a>
</div>
</div>
`)
})
}
function labelingToUser(person){}