如何解析响应.body okhttp

Question

我在通过okhttp响应解析字符串结果时遇到问题，我想解析这个字符串，但我不知道该怎么做。有人能帮我吗？

我正在使用安卓工作室。

public class MainActivity extends AppCompatActivity {
 
    private TextView mTextViewResult;
 
    @Override
    protected void onCreate(Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);
        setContentView(R.layout.activity_main);
 
        mTextViewResult = findViewById(R.id.text_view_result);
 
        OkHttpClient client = new OkHttpClient();
 
        String url = "https://reqres.in/api/users?page=2";
 
        Request request = new Request.Builder()
                .url(url)
                .build();
 
        client.newCall(request).enqueue(new Callback() {
            @Override
            public void onFailure(Call call, IOException e) {
                e.printStackTrace();
            }
 
            @Override
            public void onResponse(Call call, Response response) throws IOException {
                if (response.isSuccessful()) {
                    final String myResponse = response.body().string();
 
                    MainActivity.this.runOnUiThread(new Runnable() {
                        @Override
                        public void run() {
                            mTextViewResult.setText(myResponse);
                        }
                    });
                }
            }
        });
    }
}

块报价[｛"attributes｝：｛>message｝：｝以下是一些入门资源：\n\n-配置家庭助理\n-可用组件\n-配置疑难解答\n-获取帮助\n\n若要以后看不到此卡弹出窗口，请在configuration.yaml中编辑您的配置并禁用introduction组件{"id"："840e4ec2072144cfa7d53550796dc35d"，"parent_id"：null，"user_id"：null}，"；entity_id"："通知"last_changed"："2019-04-11T22:44:04.942593+00:00"last_updated"："2019-04-11T22:44:04.942593+00:00"状态"："通知"}，{"属性"：{"方位角"：282.29，"仰角"：37.79，"友好_名称"："太阳"，"下一个黎明"："2019-04-15T05:35+00:0"，"上一个黄昏"："2019 9-04-14T18:24:46+00:00"，"下一个中午"："2019-04-15T12:0:13+00:00"，"下一次上升"："2019 9-04-15T05:56:50+00:00"next_setting"："2019-04-14T18:03:50+00:00"}"上下文"：{"id"："a8908c263c854345a5183585553319876"，"parent_id"：null，"user_id"：null}，"；entity_id"："sun.sun"last_changed"："2019-04-14T05:57:06.013733+00:00"last_updated"："2019-04-14T15:26:3009359+000:00"状态"："above_horizon"}，由挪威气象研究所提供的met.no天气预报；https://api.met.no/weatherapi/weathericon/1.1/?symbol=10；content_type＝image/png"friendly_name"："yr符号"}"上下文"：{"id"："e2d38361a1704e2a97a78dca780e20&"，"parent_id"：null，"user_id"：null}，"；entity_id"："sensor.yr_symbol"last_changed"："2019-04-14T14:31:0098478+00:00"last_updated"："2019-04-14T14:31:0098478+00:00"状态"："10〃}，{"attributes"：{"friendly_name"："potenza massima stufa"，"last_triggered"：null}，"；上下文"：{"id"："708bfbddda494f07a11506b5e69e3add"，"parent_id"：null，"user_id"：null}，"；entity_id"："脚本1547400071844"last_changed"："2019-04-11T22:44:27.871225+00:00"last_updated"："2019-04-11T22:44:27.871225+00:00"状态"："off"}，{"attributes"：{"friendly_name"："potenza minima stufa"，"last_triggered"：null}，"；上下文"：{"id"："9721b6341250436e8050556e44015ebd"，"parent_id"：null，"user_id"：null}，"；entity_id"："脚本1547305398108"last_changed"："2019-04-11T22:44:27.872132+00:00"last_updated"："2019-04-11T22:44:27.872132+00:00"状态"："off"}，{"属性"：{"设备类别"："连接"，"友好名称"："远程UI"}；上下文"：{"id"："4429627581ef481785396af892bb92cc"，"parent_id"：null，"user_id"：null}，"；entity_id"："binary_sensor.remote_ui"last_changed"："2019-04-11T22:44:27.901163+00:00"last_updated"："2019-04-11T22:44:27.901163+00:00"状态"："不可用"}，｛"attributes"：｛"access_token"："6304d62742f4b9792101bdb83ee7a7953c1263bc7276e42e6b4f5c6b8a579253"，"entity_picture"："/api/comerate_proxy/camera.front_window？token=6304d62742f4B979201bdb83 ee7a7953C1263bc726e42e4b4f5c8a579253"，"supported_features"：0}，"；上下文"：{"id"："53ddda3891f24b2b88ecedf43d27186a"，"parent_id"：null，"user_id"：null}，"；entity_id"："camera.front_window"last_changed"："2019-04-11T22:44:27.911773+00:00"last_updated"："2019-04-14T15:22:32.548799+00:00"状态"："空闲"}，{"属性"：{"auto"：true，"entity_id"：["script.154740071844"，"script.154730339808"]，"friendly_name"："所有脚本"，"隐藏"：true、"顺序"：0}；上下文"：{"id"："d0230ccfddf4407fab7e784b3539fa3b"，"parent_id"：null，"user_id"：

块报价

Answer 1

使用Gson解析器。链接是Gson

现在，关于如何处理字符串的文档在这里

首先，通过您的请求，结果是

{
"page": 2,
"per_page": 3,
"total": 12,
"total_pages": 4,
"data": [
{
"id": 4,
"first_name": "Eve",
"last_name": "Holt",
"avatar": "https://s3.amazonaws.com/uifaces/faces/twitter/marcoramires/128.jpg"
},
{
"id": 5,
"first_name": "Charles",
"last_name": "Morris",
"avatar": "https://s3.amazonaws.com/uifaces/faces/twitter/stephenmoon/128.jpg"
},
{
"id": 6,
"first_name": "Tracey",
"last_name": "Ramos",
"avatar": "https://s3.amazonaws.com/uifaces/faces/twitter/bigmancho/128.jpg"
}
]
}

第二，声明一个类，比如这个

public class ResponseResult {
private int page;
private int per_page;
private int total;
private int total_pages;
private List<DataBean> data;
public int getPage() {
return page;
}
public void setPage(int page) {
this.page = page;
}
public int getPer_page() {
return per_page;
}
public void setPer_page(int per_page) {
this.per_page = per_page;
}
public int getTotal() {
return total;
}
public void setTotal(int total) {
this.total = total;
}
public int getTotal_pages() {
return total_pages;
}
public void setTotal_pages(int total_pages) {
this.total_pages = total_pages;
}
public List<DataBean> getData() {
return data;
}
public void setData(List<DataBean> data) {
this.data = data;
}
public static class DataBean {
private int id;
private String first_name;
private String last_name;
private String avatar;
public int getId() {
return id;
}
public void setId(int id) {
this.id = id;
}
public String getFirst_name() {
return first_name;
}
public void setFirst_name(String first_name) {
this.first_name = first_name;
}
public String getLast_name() {
return last_name;
}
public void setLast_name(String last_name) {
this.last_name = last_name;
}
public String getAvatar() {
return avatar;
}
public void setAvatar(String avatar) {
this.avatar = avatar;
}
}
}

然后，在您的改装响应中，尝试使用Gson解析String，如下所示。

Gson gson = new Gson();
ResponseResult responseResult=gson.fromJson(response.body().string(), ResponseResult.class);

现在，您可以通过对象responseResult使用它。

当然，有更简洁的方法来处理这个问题。但是我建议你应该先掌握这个方法。

Answer 2

考虑以下json:

{
"tag": "tg1",
"version": "vr1"
}

创建一个与上述内容相对应的类。

data class TermsResponse(val tag: String, val version: String)

用户retrofit定义您的API：

@GET("/v1/myapi/terms")
Observable<Response<TermsResponse>> getTerms();

使用okhttp进行api调用：

myApi.getTerms()
.subscribeOn(Schedulers.io())
.observeOn(Schedulers.computation())
.subscribe(
{ result -> showResult(result.body() as TermsResponse) },
{ error -> showError(error.message) }
)

Answer 3

这是我请求的代码

public class MainActivity extends AppCompatActivity {   
    private TextView mTextViewResult;    
 
    @Override
    protected void onCreate(Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);
        setContentView(R.layout.activity_main);
 
        mTextViewResult = findViewById(R.id.text_view_result);
 
        OkHttpClient client = new OkHttpClient();
 
        String url = "https://reqres.in/api/users?page=2";
 
        Request request = new Request.Builder()
                .url(url)
                .build();
 
        client.newCall(request).enqueue(new Callback() {
            @Override
            public void onFailure(Call call, IOException e) {
                e.printStackTrace();
            }
 
            @Override
            public void onResponse(Call call, Response response) throws IOException {
                if (response.isSuccessful()) {
                    final String myResponse = response.body().string();
 
                    MainActivity.this.runOnUiThread(new Runnable() {
                        @Override
                        public void run() {
                            mTextViewResult.setText(myResponse);
                        }
                    });
                }
            }
        });
    }
}

Answer 4

最简单的方法是使用org.json.*，如下所述：如何在Java 中解析JSON

需要注意的一点是，response.body().string()将只工作一次(如下所述：https://square.github.io/okhttp/4.x/okhttp/okhttp3/-response-body/#the-响应主体只能使用一次)，因此您可以利用这一机会将字符串主体保存到技术变量中，然后使用它。