我刚刚启动django以及我试图实现$ http.post方法的angular的方法,以向我的django数据库发布表单数据,我的进一步计划是更新视图以显示显示的视图没有页面刷新的结果。因此,我想在Django db中发布数据,然后我的视图功能将返回jsonresponse,该张贴的数据可以使用$ http.get方法来更新视图。
。但是我遇到的问题是,每当我发布数据时,都无法发布数据并返回空的JSON响应。
这是我正在处理的代码: -
urls.py
from django.conf.urls import url
from . import views
app_name='demo'
urlpatterns=[
url(r'^$',views.index,name="index"),
url(r'^add_card/$',views.add_card,name="add_card")
]
views.py
from django.shortcuts import render
from django.http import HttpResponse,JsonResponse
from .forms import CardForm
from .models import Card
# Create your views here.
def add_card(request):
saved = False
if request.method == 'POST':
#print('hi')
form = CardForm(request.POST)
#print('hi')
if form.is_valid():
#print('hi')
card = Card()
#print('hi')
card.content = form.cleaned_data['content']
#print('hi')
saved = True
card.save()
#print('hi')
return JsonResponse({'body':list(q.content for q in Card.objects.order_by('-id')[:15])})
else:
return HttpResponse(
json.dumps({"nothing to see": "this isn't happening"}),
content_type="application/json"
)
def index(request):
return render(request,'demo/index.html',{'form':CardForm()})
controller.js
var nameSpace = angular.module("ajax", ['ngCookies']);
nameSpace.controller("MyFormCtrl", ['$scope', '$http', '$cookies',
function ($scope, $http, $cookies) {
$http.defaults.headers.post['Content-Type'] = 'application/json';
// To send the csrf code.
$http.defaults.headers.post['X-CSRFToken'] = $cookies.get('csrftoken');
// This function is called when the form is submitted.
$scope.submit = function ($event) {
// Prevent page reload.
$event.preventDefault();
// Send the data.
var in_data = jQuery.param({'content': $scope.card.content,'csrfmiddlewaretoken': $cookies.csrftoken});
$http.post('add_card/', in_data)
.then(function(json) {
// Reset the form in case of success.
console.log(json.data);
$scope.card = angular.copy({});
});
}
}]);
我的型号: -
from django.db import models
# Create your models here.
class Card(models.Model):
content = models.TextField()
date = models.DateTimeField(auto_now_add=True)
def __str__(self):
return self.content
我的forms.py-
from django import forms
from .models import Card
class CardForm(forms.ModelForm):
class Meta:
model = Card
fields = ['content']
您在view.py
代码中遇到了一些问题。
- 您需要从请求数据中创建数据库中的新对象
-
您需要返回新数据作为响应
if form.is_valid(): new_content = form.cleaned_data['content'] card = Card.objects.create(content=new_content) return JsonResponse( list(Card.objects.all().order_by('-id').values('content')[:15]), safe=False )
应该返回
Card
表中前15个对象的content
值的列表,如果您的表单有效,则通过所提供的内容在该表中创建一个新对象。 -
也应定义您的
CardForm
如下:class CardForm(forms.ModelForm): class Meta: model = Card fields = ('content',)
-
最后,您的
$http.post
调用是异步的,这意味着,当达到.then
时,尚未解决邮政请求尚未解决的概率(几乎可以肯定(,因此您的json.data
是空的。解决此问题:$http.post('add_card/', in_data) .then((json) => { // Reset the form in case of success. console.log(json.data); $scope.card = angular.copy({}); });
在异步到同步的呼叫上,更好的阅读和解决方案是:ES6承诺 - 在Promise链中呼叫同步功能,您如何同步解决ES6链的承诺?以及服务工作者中的同步或顺序提取
祝你好运:(