QMessageBox用于在计算时阻止父级

Question

我想在进行计算时使用QMessageBox来阻止其父QDialog。 我遇到了这样的事情，但这不起作用。

msgBox = QtWidgets.QMessageBox()
msgBox.setWindowTitle('Working ....')
msgBox.setText("Working, please wait ...")
msgBox.setStandardButtons(QtWidgets.QMessageBox.NoButton)
msgBox.exec_()
(doing some time consuming work)
msgBox.close()

出了什么问题，我怎样才能正确地做？

Answer 1

您必须在另一个线程中执行耗时的任务，并通过信号发出任务已完成执行的信号。要关闭 QMessageBox，您必须使用 accept(( 方法：

import threading
from PyQt5 import QtCore, QtWidgets

class Worker(QtCore.QObject):
started = QtCore.pyqtSignal()
finished = QtCore.pyqtSignal()
def execute(self, func, args):
threading.Thread(target=self._execute, args=(func, args,), daemon=True).start()
def _execute(self, func, args):
self.started.emit()
func(*args)
self.finished.emit()

def consuming_work(arg1, arg2):
import time
print(arg1, arg2)
time.sleep(5)
print("finish")

if __name__ == "__main__":
import sys
app = QtWidgets.QApplication(sys.argv)
msgBox = QtWidgets.QMessageBox()
msgBox.setWindowTitle("Working ....")
msgBox.setText("Working, please wait ...")
msgBox.setStandardButtons(QtWidgets.QMessageBox.NoButton)
worker = Worker(msgBox)
worker.finished.connect(msgBox.accept)
worker.execute(consuming_work, ["Stack", "Overflow"])
msgBox.exec_()

更新：

import threading
from PyQt5 import QtCore, QtWidgets

class WorkerMessageBox(QtWidgets.QMessageBox):
started = QtCore.pyqtSignal()
finished = QtCore.pyqtSignal()
def __init__(self, parent=None):
super().__init__(parent)
self.finished.connect(self.accept)
def execute(self, func, args):
threading.Thread(target=self._execute, args=(func, args,), daemon=True).start()
return self.exec_()
def _execute(self, func, args):
self.started.emit()
func(*args)
self.finished.emit()

def consuming_work(arg1, arg2):
import time
print(arg1, arg2)
time.sleep(5)
print("finish")

if __name__ == "__main__":
import sys
app = QtWidgets.QApplication(sys.argv)
msgBox = WorkerMessageBox()
msgBox.setWindowTitle("Working ....")
msgBox.setText("Working, please wait ...")
msgBox.setStandardButtons(QtWidgets.QMessageBox.NoButton)
msgBox.execute(consuming_work, ["Stack", "Overflow"])