如何将 JSON 字符串解析为 NS 字典

Question

我正在为登录应用程序编写代码。 谁能帮我如何解析 JSON 字符串？我的代码是

-(void)connectionDidFinishLoading:(NSURLConnection *)connection
{
    NSString *loginStatus = [[NSString alloc] initWithBytes: [webData mutableBytes] length:[webData length] encoding:NSUTF8StringEncoding];
    SBJsonParser *parser = [[SBJsonParser alloc] init];
    NSArray *loginDict = [parser objectWithString:loginDict error:nil];
    [loginStatus release];
    [connection release];

Answer 1

示例数据：

NSString *strData = @"{"1": {"name": "Jerry","age": "12"}, "2": {"name": "Bob","age": "16"}}";
NSData *webData = [strData dataUsingEncoding:NSUTF8StringEncoding];
NSError *error;
NSDictionary *jsonDict = [NSJSONSerialization JSONObjectWithData:webData options:0 error:&error];
NSLog(@"JSON DIct: %@", jsonDict);

NSLog 输出：

JSON DIct: {
     1 =     {
         age = 12;
         name = Jerry;
     };
     2 =     {
         age = 16;
         name = Bob;
     };
}

Answer 2

//*************Static Resopnse
NSString *filePath = [[NSBundle mainBundle] pathForResource:@"demo" ofType:@"text"];
NSLog (@"Content: %@", filePath);
NSString *content = [[[NSString alloc] initWithContentsOfFile:filePath
                                                 usedEncoding:nil
                                                        error:nil] autorelease];
SBJSON *json = [[SBJSON new] autorelease];
NSString *str=[[NSString alloc]initWithString:content];
dictTemp = [json objectWithString:str error:nil];
NSLog(@"Actions is: %@",dictTemp);
NSArray *arr=[[dictTemp valueForKey:@"Data"] mutableCopy];
arrX=[[NSMutableArray alloc] init];
arrY=[[NSMutableArray alloc] init];
for(NSDictionary *dict in arr)
{
    [arrX addObject:[dict valueForKey:@"Milestone"]];
    [arrY addObject:[dict valueForKey:@"Sites"]];
}   
NSLog(@"X is: %@",[arrX description]);
NSLog(@"Y is: %@",[arrY description]);

Answer 3

NSString *loginStatus = [[NSString alloc] initWithBytes: [webData mutableBytes] length:[webData length] encoding:NSUTF8StringEncoding]
NSLog([[loginStatus JSONValue] description],nil);
//This will give you parsed output.

Answer 4

   NSString *responseString = [[NSString alloc] initWithData:responseData encoding:  NSASCIIStringEncoding];
   NSlog(@"json String is: %@",responseString);
   NSDictionary *dictionary = [responseString JSONValue];
   NSLog(@"Dictionary value is  %@", [dictionary objectForKey:@"json"]);

此代码的结果是：json 字符串为：{"json"：{"成功"："激活码。

对话后，结果为-------字典值为 { 成功 ="激活码"。