我在JSON中有一个文件夹结构,需要将其反序列化为c#对象。我想知道如何在不设置多个子类对象的情况下做到这一点(因为可能有大量的子文件夹)。我在想,也许一个继承父对象的子对象,或者拥有一个包含自己的对象可能是可行的,但我被难住了!
干杯!
JSON结构:
[
{
type: "folder",
name: "animals",
path: "/animals",
children: [
{
type: "folder",
name: "cat",
path: "/animals/cat",
children: [
{
type: "folder",
name: "images",
path: "/animals/cat/images",
children: [
{
type: "file",
name: "cat001.jpg",
path: "/animals/cat/images/cat001.jpg"
}, {
type: "file",
name: "cat001.jpg",
path: "/animals/cat/images/cat002.jpg"
}
]
}
]
}
]
}
]
Json2CSharp输出:
public class Child3
{
public string type { get; set; }
public string name { get; set; }
public string path { get; set; }
}
public class Child2
{
public string type { get; set; }
public string name { get; set; }
public string path { get; set; }
public List<Child3> children { get; set; }
}
public class Child
{
public string type { get; set; }
public string name { get; set; }
public string path { get; set; }
public List<Child2> children { get; set; }
}
public class RootObject
{
public string type { get; set; }
public string name { get; set; }
public string path { get; set; }
public List<Child> children { get; set; }
}
只要结构一直都是一样的,你就应该只需要这样的东西:
public class Node {
public string type {get;set;}
public string name {get;set;}
public string path {get;set;}
public List<Node> children {get;set;}
}
依赖于这样一个事实,即如果列表是null
,则大多数序列化程序将完全忽略该列表。
例如,通过Jil
:
List<Node> nodes = Jil.JSON.Deserialize<List<Node>>(json);
和序列化:
var obj = new List<Node>
{
new Node
{
type = "folder",
name = "animals",
path = "/animals",
children = new List<Node>
{
new Node
{
type = "folder",
name = "cat",
path = "/animals/cat",
children = new List<Node>
{
new Node
{
type = "folder",
name = "images",
path = "/animals/cat/images",
children = new List<Node>
{
new Node
{
type = "file",
name = "cat001.jpg",
path = "/animals/cat/images/cat001.jpg"
},
new Node {
type = "file",
name = "cat001.jpg",
path = "/animals/cat/images/cat002.jpg"
}
}
}
}
}
}
}
};
string json = Jil.JSON.Serialize(obj, Jil.Options.PrettyPrint);
当你说C# object
时,我喜欢认为没有涉及自定义定义的类。您可以使用dynamic
:
var serializer = new JavaScriptSerializer();
serializer.RegisterConverters(new[] { new DynamicJsonConverter() });
dynamic obj = serializer.Deserialize(e.Parameters, typeof(object));
然后你可以访问这样的属性:
string type = obj.type as string;
string name = obj.name as string;
...
DynamicJsonConverter
的代码可以在此处找到