抓取文件的每一行，并增加值

Question

我有一个带有行的文件：

[tree]:1,"asdf"
[box]:2,"yuio"
[bee]:10,"rtyu"
[cup]:15,"bnmv"
[tree]:13,"asdf"

我希望输出为

[tree]:2,"asdf"
[box]:2,"yuio"
[bee]:10,"rtyu"
[cup]:15,"bnmv"
[tree]:14,"asdf"

因此，我需要将[树]值增加1。我需要某种方法来搜索[TEER]，复制其旁边的数字，该数字可能超过2位数字，然后递增此数字。我已经在MATLAB中完成了此操作，但痛苦慢，涉及重写整个文件。我正在寻找更快的替代方案，例如bash脚本或python中的东西。

Answer 1

def incrementKeys(infilepath, outfilepath, keys, incrementBy):
    with open(infilepath) as infile, open(outfilepath, 'w') as outfile:
        for line in infile:
            if any(line.startswith(key) for key in keys):
                k, tail = line.split(',')
                k, val = k.split(":")
                val = int(val)+incrementBy
                line = "%s:%d,%sn" %(k, val, tail)
            outfile.write(line)

Answer 2

尝试以下：

f = file("file.txt")
for l in f:
    if l[:6] == "[tree]":
        s = "".join([l[:l.find(":")+1], str(int(l[l.find(":")+1:l.find(",")])+1), l[l.find(","):]])
        print s

而不是print，请按照结果做任何您喜欢的事情。例如，您可以再次将其写入文件。