我需要将insert
语句写入表中,列如下所示
-
demandtypeid
(PK, FK, int, not null
) -
characvalueid
(PK, FK, int, not null
) -
percentage
(int null
) -
lastuser
(varchar(100), null
) -
lastedited
(datetime, null
)
这是INSERT
声明。请注意,在
value( , , 'Bob')
因为我认为这就是自动增量命令应该去的地方
insert into tr_demandtypecharac(demandtypeID, characvalueid, lastuser)
values( , , 'Bob')
请帮忙做一个简单的小陈述
我只想知道如何手动插入到此表中
这是我的表结构:
CREATE TABLE [dbo].[tr_demandtypecharac](
[demandtypeid] [int] NOT NULL,
[characvalueid] [int] NOT NULL,
[percentage] [int] NULL,
[lastuser] [varchar](100) COLLATE SQL_Latin1_General_CP1_CI_AS NULL,
[lastedited] [datetime] NULL,
CONSTRAINT [PK_tr_dtc_pkey] PRIMARY KEY CLUSTERED
(
[demandtypeid] ASC,
[characvalueid] ASC
)WITH (IGNORE_DUP_KEY = OFF) ON [PRIMARY]
) ON [PRIMARY]
ALTER TABLE [dbo].[tr_demandtypecharac] WITH CHECK
ADD CONSTRAINT [FK_tr_dtc_cvid]
FOREIGN KEY([characvalueid]) REFERENCES [dbo].[tr_characvalue] ([characvalueid])
ALTER TABLE [dbo].[tr_demandtypecharac] WITH CHECK
ADD CONSTRAINT [FK_tr_dtc_dtid]
FOREIGN KEY([demandtypeid]) REFERENCES [dbo].[tr_demandtype] ([demandtypeid])
如果您想要一个唯一且自动递增的 int 列,请使用 IDENTITY
关键字:
CREATE TABLE new_employees
(
id_num int IDENTITY(1,1),
fname varchar (20),
minit char(1),
lname varchar(30)
)
然后,当您插入到表中时,不要为该列插入任何内容 - 它会自动递增。
给定您发布的 CREATE TABLE
语句,如果没有自动增量(又名身份)列,您将插入提供所有列和值的内容,如下所示:
insert into tr_demandtypecharac(
demandtypeid, characvalueid,
percentage, lastuser, lastedited)
values(2, 3, 80, 'Bob', '01/01/2012')
但是,如果您确实通过将CREATE TABLE
更改为:
CREATE TABLE [dbo].[tr_demandtypecharac](
[demandtypeid] [int] NOT NULL IDENTITY(1,1),
[characvalueid] [int] NOT NULL IDENTITY(1,1),
[percentage] [int] NULL,
[lastuser] [varchar](100) COLLATE SQL_Latin1_General_CP1_CI_AS NULL,
[lastedited] [datetime] NULL,
CONSTRAINT [PK_tr_dtc_pkey] PRIMARY KEY CLUSTERED
(
[demandtypeid] ASC,
[characvalueid] ASC
)WITH (IGNORE_DUP_KEY = OFF) ON [PRIMARY]
)
然后,您将插入提供所有非标识(非自动增量)列,如下所示:
insert into tr_demandtypecharac(
percentage, lastuser,
lastedited)
values(80, 'Bob', '01/01/2012')
但是,将多个列作为标识(自动增量)列并不常见,通常,此列是唯一的主键列。
如果列是自动强化列(不同于主键列),则在 insert 语句中省略该列,它将被填充。
INSERT INTO tr_demandtypecharac (lastuser) VALUES ('Bob')
我遇到了类似的问题,需要使用一组记录更新购买的数据库。 我的解决方案是找到到目前为止使用的最高键,然后将其用作插入的基础。 它的核心是 ROWNUMBER() OVER(ORDER BY PART_CODE)。
关键是 inadjinf 表中的 "recnum" 字段。 我确定当前最高密钥是 675400,并将查询更新为:
insert into inadjinf (recnum, user_id, adj_type, adj_status, trans_date, part_code, lotqty, uom, cost_ctr, lot, location, to_cost_ctr, to_location, rec_status, to_part_grade, to_rec_status, remarks1, uom_conv)
select ROW_NUMBER() OVER(ORDER BY INVDET.PART_CODE) + 675400 as recnum, 'CHRSTR' as user_id, 'M' as adj_type, 'O' as adj_status, '2020-10-23' as trans_date, invdet.part_code, sum(lotqty) as lotqty, uom,
cost_ctr, lot, location, 'NS' as to_cost_ctr, '500A' as to_location, rec_status, 'Q' as to_part_grade, 'H' as to_rec_status, 'NS Scrap Request from MSobers 10/21/2020' as remarks1, '1' as uom_conv
from invdet
inner join partmstr on invdet.part_code = partmstr.part_code
where
invdet.part_code In
(
'86038',
'1271',
'VM-0021',
'CO-0107',
...
'FO-0391',
'FO-0376'
)
and lot not in (select lot from inadjinf where trans_date = '2020-10-23' and user_id = 'CHRSTR')
group by invdet.part_code, uom, cost_ctr, lot, location, rec_status
我的输出从675401开始,然后从那里上升。 最后,我更新了系统的内部"下一个 id 字段"表记录。
你不应该使用 int 作为主键...这里有一篇关于它的文章: http://techtrainedmonkey.com/2012/07/30/why-integers-are-lousy-primary-keys/
但是如果你这样做......将字段设置为身份,SQL Server将为你做...看看: http://msdn.microsoft.com/en-us/library/ms186775.aspx