c 将每行的数字组合在一个文本文件中

Question

我有一个有很多行的文本文件，我复制粘贴其中一些在这里，向您展示我正在使用什么。

1 16.07.2011 kl. 17.00 OB - FCN 2 - 0 6.965
1 17.07.2011 kl. 14.00 FCM - SIF 1 - 2 5.370

2 23.07.2011 kl. 17.00 SIF - BIF 0 - 1 4.173
2 23.07.2011 kl. 19.00 FCK - OB 2 - 2 14.774
3 30.07.2011 kl. 17.00 AGF - OB 2 - 2 11.312
3 30.07.2011 kl. 19.00 FCK - FCN 2 - 0 11.076

while (fscanf(ifp, "%d %d.%d.%d kl. %lf %4s - %4s %d - %d %lfn", &runde, &dag, &month, &year, &clock, team1, team2, &goal1, &goal2, &attendance) == 10)
    int prev_goal = goal1 + goal2;
    int current;
    if(prev_goal > current) {
    printf("Runde %d var den mest målrige med %d måln", runde, prev_goal);
   }

我将值放入不同的变量中，但是如何将每轮的结果相加，看看哪一轮的进球最多？任何建议将不胜感激！谢谢:)

Answer 1

我将假设您只关心哪个回合的进球最多，并且您不需要像@Ben建议的那样将文本文件存储在内存中。

如果是这种情况，您可以执行以下操作：

int i, maxGoals = 0, roundWithMostGoals = 0;
for (i = 0; fscanf(ifp, "%d %d.%d.%d kl. %lf %4s - %4s %d - %d %lfn", &runde, &dag, &month, &year, &clock, team1, team2, &goal1, &goal2, &attendance) == 10; ++i)
{
    if (maxGoals < goal1 + goal2)
    {
        roundWithMostGoals = runde;
        maxGoals = goal1 + goal2;
    }
}
// Edit:
printf("The largest number of goals was %d, scored in round %d", maxGoals, roundWithMostGoals);

此代码确实有问题。如果有两轮进球数最多，则只打印第一轮。

为了避免这种情况，我们需要循环两次，这并不理想，我建议使用其他建议的方法之一，将所有这些数据加载到内存中。

但是，这里有一个修改后的解决方案，如上面所示，即使我认为它不是最佳的：

int i, maxGoals = 0, roundWithMostGoals = 0;
// Find the maximum number of goals that was scored in any one round.
for (i = 0; fscanf(ifp, "%d %d.%d.%d kl. %lf %4s - %4s %d - %d %lfn", &runde, &dag, &month, &year, &clock, team1, team2, &goal1, &goal2, &attendance) == 10; ++i)
{
    if (maxGoals < goal1 + goal2)
    {
        maxGoals = goal1 + goal2;
    }
}
printf("The largest number of goals scored was %d.n", maxGoals);
printf("The largest number of goals was scored inn");
// TODO: Reposition the file stream back to the beginning or close it and then reopen it again.
// XXX Code Here XXX
// Loop through again getting all the rounds with the maximum number of goals.
for (i = 0; fscanf(ifp, "%d %d.%d.%d kl. %lf %4s - %4s %d - %d %lfn", &runde, &dag, &month, &year, &clock, team1, team2, &goal1, &goal2, &attendance) == 10; ++i)
{
    if (maxGoals == goal1 + goal2)
    {
        printf("tRound %dn", runde);
    }
}

但是现在循环了两次，绝对不是解决您问题的最佳方法。

Answer 2

你应该做一些数组：

int goal1Array[]
int goal2Array[]
int listLength = 0;

然后，当您阅读目标时，您可以将它们添加到数组中（确保记录要添加的数量）：

goal1Array[9] = goal1;
listLength++;

注：您将需要执行一些动态内存管理。查找 c 数组等。

最后，您可以循环浏览此列表以比较它们：

for (i = 0; i < listLength; i++) {
    /*compare stuff*/
}

这只是一些一般建议，您需要付出一些努力才能在没有内存错误的情况下进行编译。

祝你好运。

Answer 3

为每个团队制作一个带有 int 的整数数组。它们将是每个团队的总和。

然后，将团队 1 和团队 2 的名称与团队的名称进行 strcmp 。然后，将目标添加到其关联的目标总和中。

int goalSum[3];
goalSum[0] = 0;goalSum[1] = 0;goalSum[2] = 0

while (fscanf(ifp, "%d %d.%d.%d kl. %lf %4s - %4s %d - %d %lfn", &runde, &dag, &month, &year, &clock, team1, team2, &goal1, &goal2, &attendance) == 10)
{
    //comparisions for the first team
    if(strcmp(team1,"nameofteam0")==0)
    {
            ++goalSum[0];
    }
    if(strcmp(team1,"nameofteam1")==0)
    {
            ++goalSum[1];
    }
    if(strcmp(team1,"nameofteam2")==0)
    {
            ++goalSum[2];
    }
    //comparisions for the second team
    if(strcmp(team2,"nameofteam0")==0)
    {
            ++goalSum[0];
    }
    if(strcmp(team2,"nameofteam1")==0)
    {
            ++goalSum[1];
    }
    if(strcmp(team2,"nameofteam2")==0)
    {
            ++goalSum[2];
    }
}

然后，比较每个团队的目标。

    const int numberOfTeams = 3;
    int winningTeam=0;
//You'll have to do the support for draws yourself.
    for(int i = 0; i<numberOfTeams; ++i)
    {
        if(sumOfGoal[i]>sumOfGoal[i+1])
        {
                winningTeam = i+1;
        }
        else
        {
                winningTeam = i+2;
        }
    }
    printf("Team%i wins!n", winningTeam);