如何根据Bash中的定界符分开字符串

Question

我已经在一个.sh文件中定义了一个数组：

hosts=(NODE IPS)
hosts[0]="1.110,Node-01"
hosts[1]="1.111,Node-02"
hosts[2]="1.112,Node-03"
hosts[3]="1.113,Node-04"
hosts[4]="1.114,Node-05"
hosts[5]="1.115,Node-06"

我如何在数组上循环，但是根据通信分配每个索引，并将值存储在变量中，类似的内容：

for index in ${!hosts[*]}
do
    ip = ## some way to split the string, and get the left side of the index
    hostname = ## some way to split the string, and get the right side of the index
    ## do something with the above variables
    echo "IP: $ip HOSTNAME: $hostname"
done

我正在使用Linux，如果这有帮助

Answer 1

for host in "${hosts[@]}"; do
    IFS=, read ip hostname <<< "$host"
    echo "IP: $ip, HOSTNAME: $hostname"
done

Answer 2

尝试此-->

1. 使用tr打破字符串

   for w in $(echo "hello/Hi/Bye" | tr "/" " ") ; do echo $w; done
   

   输出

   Hello
   Hi
   Bye
   

2。可以使用awk语句。示例--->使用"："作为以下示例的定界符

$ echo "abc:def" | awk -F':' '{print "field1: "$1 "nfield2: "$2}'

输出

field1: abc
field2: def