我尝试使用GraphStream库来查找图中2个节点之间的最短路径。最后,我能够打印路径的边缘(it.foreach(println)
),但我不能一次访问一个元素。这是代码:
import org.graphstream.algorithm.Dijkstra;
import org.graphstream.graph.Edge;
import org.graphstream.graph.Graph;
import org.graphstream.graph.Node;
import org.graphstream.graph.Path;
import org.graphstream.graph.implementations.SingleGraph;
import scala.collection.JavaConverters._
object MainApp extends App{
def exampleGraph():Graph={
val g:Graph = new SingleGraph("example");
g.addNode("N1_S1");
g.addNode("N1_J1");
g.addNode("N1_H1");
g.addNode("N1_J2");
g.addNode("N1_H2");
g.addNode("N1_W1");
var e:Edge=g.addEdge("N1_S1-N1_J1", "N1_S1", "N1_J1")
e.addAttribute("length",Int.box(6))
e=g.addEdge("N1_J1-N1_H1", "N1_J1", "N1_H1")
e.addAttribute("length",Int.box(8))
e=g.addEdge("N1_J1-N1_J2", "N1_J1", "N1_J2")
e.addAttribute("length",Int.box(8))
e=g.addEdge("N1_J2-N1_H2", "N1_J2", "N1_H2")
e.addAttribute("length",Int.box(4))
e=g.addEdge("N1_J2-N1_W1", "N1_J2", "N1_W1")
e.addAttribute("length",Int.box(10))
return g
}
val g:Graph = exampleGraph();
g.display(false);
val dijkstra:Dijkstra = new Dijkstra(Dijkstra.Element.EDGE, null, "length");
dijkstra.init(g);
dijkstra.setSource(g.getNode("N1_S1"));
println(dijkstra.getPath(g.getNode("N1_W1")));
val myPath:Path=dijkstra.getPath(g.getNode("N1_W1"))
val it=(myPath.getEachEdge).asScala
println("edges")
it.foreach(println)
}
问题是getEachEdge
的原型是getEachEdge[T <: Edge](): Iterable[_ <: T]
,而asScala
返回的是Iterable[_ <: Nothing]
。最后一个问题是"如何访问最短路径中的每个元素?"
我不知道为什么,但是你必须显式地注释类型。
myPath.getEachEdge[Edge].asScala
如果指定了错误的子类型,可能会得到运行时强制转换异常。
抛出ClassCastException:
@ trait OtherEdge extends Edge
defined trait OtherEdge
@ myPath.getEachEdge[OtherEdge].asScala.head
java.lang.ClassCastException: org.graphstream.graph.implementations.AbstractEdge cannot be cast to $sess.cmd17$OtherEdge
$sess.cmd18$.<init>(cmd18.sc:1)
$sess.cmd18$.<clinit>(cmd18.sc:-1)
尝试用类型注释帮助编译器:
val it: Iterable[Edge] = myPath.getEachEdge.asScala